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Margarita [4]
3 years ago
13

A conical water tank with vertex down has a radius of 10 feet at the top and is 20 feet high. If water flows into the tank at a

rate of 10 ft3/minft3/min, how fast is the depth of the water increasing when the water is 15 feet deep?
Mathematics
1 answer:
tester [92]3 years ago
5 0
Since r=h/2 and V=(hpr^2)/3

V=(ph^3)/12

V(15)=281.25p and since V=10t, t=28.125p

V=(ph^3)/12

dV/dh=(3ph^2)/12=(ph^2)/4  and since V=10t, dV/dt=10

(dh/dV)(dV/dt)=dh/dt=12/(3ph^2)*10

dh/dt=120/(3ph^2)  and we want the rate when h=15 so

dh/dt(15)=120/(675p)

dh/dt=0.05658 ft/min  
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Look at triangles TUV and T'U'V'.Which best explains the transformation of triangle TUV to form triangle T'U'V'?​
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4 0
3 years ago
a recipe uses 1 1/4 cups of milk to make 10 servings. if the same amount of milk is used for each serving, how many servings can
Anestetic [448]

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128 servings can be made using 1 gallon of milk.

Step-by-step explanation:

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3 0
3 years ago
Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,
Sholpan [36]
A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
d^2=3^2+2^2
d^2=9+4
d^2=13
d= \sqrt{13}
We can conclude that the distance between my house and the movie theater is \sqrt{13}

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
d^2=6^2+5^2
d^2=36+25
d^2=61
d= \sqrt{61}
We can conclude that the distance between the police station and the airport is \sqrt{61}

C. Distance form the park to the Fire Station:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance from the park to the Fire Station is \sqrt{10}

Distance from the stadium to the mall:
d^2=2^2+1^2
d^2=4+1
d^2=5
d= \sqrt{5}
We can conclude that the distance from the stadium to the mall is \sqrt{5}

D. What is the distance between your house and the mall?
Answer:
d^2=4^2+4^2
d^2=16+16
d^2=32
d= \sqrt{32}
d=4 \sqrt{2}
We can conclude that the distance between my house and the mall is 4 \sqrt{2}

What is the distance between the movie theater and the school?
answer:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance between the movie theater and the school is \sqrt{10}

7 0
2 years ago
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