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german
3 years ago
5

The ship Mark travels from Halo dock to Oregon dock in Liverpool. At the same time, a ship called Annie travels from Oregon dock

to Halo dock. Annie is 12MPH faster than Mark. They pass by each other 15 minutes after departure. (A) What are the speeds of the ships, if the docks a 5 miles apart (B) How far did each ship sail before they met? (Mind the units)
Mathematics
1 answer:
nikitadnepr [17]3 years ago
6 0

Answer:

A) Mark speed = 7mph  Annie speed is 1.2miles faster at 8.2mph

B) Mark had sailed ratio to Annie 17.5: 20.5

= 3mph faster in 15 minutes This makes it 12mph faster every 5 hrs

The percentage speed of Mark is 83% of 100% of Annie.

This makes Annie 7% faster

7% of 7mph = 1.2 so it has to be 1.2miles faster and not 12mph faster to meet at 15minutes.

Step-by-step explanation:

Annie is 12mph faster they pass 15mins after departure

= 0-15= Annie is 4mp faster than Mark at 15mins.

Annie = 5 miles = m+60m = 60 this makes mark 5.6 : 6 ratio per 15 minutes 28:30 = 1.4 : 1.5 ratio at 15 minutes.

Mark = 5 miles = 5 x 1.4 =7mph + 0m = 7mph

Annie = 5 miles = 5 x 1.5 = 7.5mph + 7 = 8.2mph

A=We can check that 1/4 of 8.2mph distance = 2.5 per 15mins

M=We can check that 1/4 of 7.0mph distance = 1.75 per 15mins

A=We can check that 2.05 per 15mins = 2.5 x 4  = 8.2 mph = 41miles in 5 hr

M=We cna check that 1.75 per 15mins = 1.7 x 4 x 5= 7mph = 35 miles every 5hr

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sveticcg [70]

Given:

Length of the scale = 15.6 in.

Width of the scale = 7.2 in.

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To find:

The ratio of area of the actual court to the area of the drawing (as a unit rate).

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Step-by-step explanation:

We have,

1 in. = 5ft.

Now, using this scale we get

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7.2 in. = (7.2 × 5) ft = 36 ft.

So, the actual length and width of tennis court are 78 ft and 36 ft respectively.

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The area of drawing is

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Now, ratio of area of the actual court to the area of the drawing (as a unit rate) is

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Therefore, the ratio of area of the actual court to the area of the drawing (as a unit rate) is 25:1.

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Answer:

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