Question

F(x) = 8-4x+X² g(x) = 2x² +5x-1 find f(x) + g(x)

Answer 1

Answer:  " $3x^{2} -4x +7$ " .

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Step-by-step explanation:

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We are to find the following sum:

  Add:  $f(x) + g(x)$  .

Given:  $f(x)= 8-4x +4x^{2}$  ;

Rewrite as follows:

             $f(x) =x^{2}-4x+8$ ;

{Note:  Since:  $f(x) = +8 + (-4x) + x^{2}$ ;  we can rearrange the terms;

   and rewrite by starting in the order of the highest degree monomial

(i.e., the term among the 3 (three) monomials containing the variable with the highest exponential value—which is:  "$x^{2}$ " ; and continue in descending order; with   " $(-4x^{1})$" ;  which is:  " $-4x$ " ; [with the 'implied exponent of "1" ; since any value, raised to the exponent, "1" ; ["first power"]; resulting in that same value.   Then, we finish with the last monomial, " $(+8x^0)$ ";  which is:  "(+8x) " —with the implied exponent of "0" ; since any non-zero value; raised to the "0th" exponent ['raised to the power of zero']; results in the value of "1" .  

       →  As such:  "  +8x  =  +8x⁰ " ;

                      ↔ "  +8x⁰ = (+8) * (x⁰) = (+8) * (1) =  " (+8) ;

→  {since any value, multiplied by "1" ; results in that same value;  this refers to the "identity property" of multiplication.}.

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So, plug in:  " $x^{2}-4x+8$ " ;  for:  " $f(x)$ " ;

And plug in the given:  " $2x^{2} + 5x -1$ " ;  for " $g(x)$ " ;

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And add the sum:

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→        $f(x) +g(x) = (x^{2}-4x+8)+(2x^2+5x-1)$  ;

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                            $= x^{2} -4x+8+2x^{2} -1$ ;

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         →  Now, combine the "like terms" ; and simplify:

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         →   $+x^{2} +2x^{2} =+3x^{2}$ ;

         →   $-4x$  ;  stands alone;

         →   $+8 -1 = + 7$ ;

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→  Now; we have accounted for All of the terms in our expression;

and we can write out our answer:

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   →  which is:  " $3x^{2} -4x +7$ " .

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Hopefully—this answer and explanation is helpful to you.

  Wishing you the best in your academic pursuits!

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Answer 2

Answer:

IN THE PICTURE

Step-by-step explanation:

...IN THE PICTURE

..ur welcome, have a noice day

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