Answer:
A
Step-by-step explanation:
The line is divided into 9 parts between 1 and 2
A is situated 6 parts of the way between 1 and 2, that is
= 
← cancelling by 3
Hence
A = 1 + = 1 → A
Answer:
The number of boxes of candy sold is 4
The number of rolls of wrapping paper sold is 10
Step-by-step explanation:
Let x = number of boxes of candy that was sold.
Let y = number of rolls of wrapping paper was sold.
The candy sells for 8 dollars per box and the wrapping paper sells for 6 dollars per roll. This means that x boxes of candy and y rolls of wrapping paper will be sold for
$(8x + 6y)
If you have sold 14 items, and collected 92 dollars, this means that
x + y = 14
8x + 6y = 92 - - - - - - -1
Substituting x = 14 - y into equation 1, it becomes
8(14-y) + 6y = 92
112 - 8y + 6y = 92
- 8y + 6y = 92 - 112
-2y = -20
y = 20/2 = 10
x = 14 - y
x = 14 - 10
x = 4
The number of boxes of candy sold is 4.
The number of rolls of wrapping paper sold is 10.
Answer:
Step-by-step explanation:
The problem statement defines the variables and gives the relations ...
2b + f = 8 . . . . total cost on Monday
3b + f = 11 . . . . total cost on Tuesday
__
Subtracting the first equation from the second, we get ...
(3b +f) -(2b +f) = 11 -8
b = 3 . . . . . simplify
Substituting this into the first equation, we can solve for f
2·3 +f = 8
f = 2 . . . . . . . subtract 6
Bagels cost $3 per dozen; the delivery fee is $2.
