Answer:
(30/40)*(29/39) = 29/52 =~ 0.55769
Step-by-step explanation:
The probability is calculated assuming the cars were chosen without replacement .
.026 because 2.6%*100 is 0.026
1. (70 - 44) / 2
2. (45.00 - 25.50) / 6
3. (75 - 39) / 3
4. (90 - 30 +10) / 3
5. (100- 30+10) / 10
6. (50 - 5) / 10
PS: / means divide or division. also remember PEMDAS
Hope this helped you (;
Answer:
19
Step-by-step explanation:
9+10=19
Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
