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3 years ago

10

2+10 x 5 - 9 idk the answer

2 answers:

Phoenix [80]3 years ago

6 0

Answer:

51

Step-by-step explanation:

12 times 5 is 60 -9 is 51

ziro4ka [17]3 years ago

6 0

Answer: 43

Step-by-step explanation:n follow PEMDAS (P= parenthesis E= exponents M=multiplication D=division A= addition S=subtraction)

2+10×5-9

2+50-9

52-9

43

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A certificate of deposit with $600 principal earns 2. 5% interest for 6 years. How much is the interest earned for 6 years?

mario62 [17]

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2 years ago

Please answer with process

laila [671]

$\mathsf{Given : a - b = 5}$

$\mathsf{Squaring\;on\;both\;sides,\;we\;get :}$

$\mathsf{\implies (a - b)^2 = 5^2}$

$\mathsf{\implies a^2 + b^2 - 2(a.b) = 25}$

$\mathsf{Given : a^2 + b^2 = 29}$

$\mathsf{\implies 29 - 2(a.b) = 25}$

$\mathsf{\implies 2(a.b) = 29 - 25}$

$\mathsf{\implies 2(a.b) = 4}$

$\mathsf{\implies (a.b) = 2}$

6 0

3 years ago

Insert geometric means in each geometric sequence.

Digiron [165]

Answer:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the $n^{th}$ term of a geometric sequence.

$a_n=ar^{n-1}$

Where $a$ is the first term and

$r$ is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

$ar = 24\\ar^4 = \dfrac{3}{64}$

Solving the above equation:

$r = \dfrac{1}{8}$

Therefore, the sequence is:

$\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}$

Considering the second given sequence:

$ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2$

Therefore, the sequence is:

$\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}$

Considering the third sequence:

$a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3$

Therefore, the sequence is:

$81, \underline{27, 9, 3, 1},\dfrac{1}{3}$

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3 years ago

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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