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uysha [10]
3 years ago
6

Whats the volume of a rectangular solid with 6 meters in length, 3 meters in width, and 7 meters in height?

Mathematics
1 answer:
pychu [463]3 years ago
7 0
The answer to your question is V = 126m
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Tell whether (12, 43) is a solution of y = 3x + 7.<br> yes<br> no
Len [333]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
5 1/3 + ( 2 1/3 + 1 1/3)=
Fiesta28 [93]
Okay so you want to do the parentheses first okay? So 2.3333...+1.3333333 is?3.666 or 3 2/3. So you got that right? So then 5 1/3+ 3 2/3. You get an easy 9. Because 1/3+ 2/3 adds up to 3/3, and is normally written as 1. So add a one to 5+3=8+1.
6 0
3 years ago
Read 2 more answers
A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)=74,000+80x
SOVA2 [1]

Answer:

a) $675000

b) $289000 profit,3300 set, $190 per set

c) 3225 set, $272687.5 profit, $192.5 per set

Step-by-step explanation:

a) Revenue R(x) = xp(x) = x(300 - x/30) = 300x - x²/30

The maximum revenue is at R'(x) =0

R'(x) = 300 - 2x/30 = 300 - x/15

But we need to compute R'(x) = 0:

300 - x/15 = 0

x/15 = 300

x = 4500

Also the second derivative of R(x) is given as:

R"(x) = -1/15 < 0 This means that the maximum revenue is at x = 4500. Hence:

R(4500) = 300 (4500) - (4500)²/30 = $675000  

B) Profit P(x) = R(x) - C(x) = 300x - x²/30 - (74000 + 80x) = -x²/30 + 300x - 80x - 74000

P(x) = -x²/30 + 220x - 74000

The maximum revenue is at P'(x) =0

P'(x) = - 2x/30 + 220= -x/15 + 220

But we need to compute P'(x) = 0:

-x/15 + 220 = 0

x/15 = 220

x = 3300

Also the second derivative of P(x) is given as:

P"(x) = -1/15 < 0 This means that the maximum profit is at x = 3300. Hence:

P(3300) =  -(3300)²/30 + 220(3300) - 74000 = $289000  

The price for each set is:

p(3300) = 300 -3300/30 = $190 per set

c) The new cost is:

C(x) = 74000 + 80x + 5x = 74000 + 85x

Profit P(x) = R(x) - C(x) = 300x - x²/30 - (74000 + 85x) = -x²/30 + 300x - 85x - 74000

P(x) = -x²/30 + 215x - 74000

The maximum revenue is at P'(x) =0

P'(x) = - 2x/30 + 215= -x/15 + 215

But we need to compute P'(x) = 0:

-x/15 + 215 = 0

x/15 = 215

x = 3225

Also the second derivative of P(x) is given as:

P"(x) = -1/15 < 0 This means that the maximum profit is at x = 3225. Hence:

P(3225) =  -(3225)²/30 + 215(3225) - 74000 = $272687.5

The money to be charge for each set is:

p(x) = 300 - 3225/30 = $192.5 per set

When taxed $5, the maximum profit is $272687.5

3 0
3 years ago
How do you solve the problem 2p = 60 ​
d1i1m1o1n [39]
You have to separate the 2 and p so divide 60 by 2 which will leave p=30 and now if you plug it in you see 2 times 30 equals 60 :)
4 0
3 years ago
Maria looked at the architectural plan of a room with four walls in which the walls meet each other at right angles. The length
babymother [125]
Using the Pythagorean theorm, 
a^2 + b^2 = C^2, where a nd b are the side lengths and c is the hypotenuse ( diagonal line)

If it was a square both sides would be the same length so we would have:
13^2 +13^2 = c^2
169 + 169 = c^2
338 = c^2

c = SQRT(338) = 18.38

18.38 is larger than the 15.26 given in the problem , so the room is not a square.
4 0
3 years ago
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