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Semenov [28]
3 years ago
14

A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test.

Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, determine which system of inequality best explains whether the company can build 10 child bikes and 12 adult bikes in the week. No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100
Mathematics
1 answer:
Bess [88]3 years ago
3 0

Answer:

4c+6a\leq120\\\\4c+4a\leq100

Step-by-step explanation:

Let c represents child bikes and a represents adult bikes.

Given :  Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test.

With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week.

Then, the required system of inequality :-

4c+6a\leq120----(1)\\\\4c+4a\leq100-----(2)

If company make 10 child bikes and 12 adult bikes in the week.

Then Put c=10 and a=12 bikes in (1) and (2).

4(10)+6(12)=40+72=112\leq120⇒Bike order meets the restrictions

4(10)+4(12)=40+48=88\leq100⇒Bike order meets the restrictions

Hence, the system of inequality best explains whether the company can build 10 child bikes and 12 adult bikes in the week.

4c+6a\leq120\\\\4c+4a\leq100

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Work out the area of abcd.<br><br> please ensure you give workings out too.
ipn [44]

Answer:

\displaystyle A_{\text{Total}}\approx45.0861\approx45.1

Step-by-step explanation:

We can use the trigonometric formula for the area of a triangle:

\displaystyle A=\frac{1}{2}ab\sin(C)

Where a and b are the side lengths, and C is the angle <em>between</em> the two side lengths.

As demonstrated by the line, ABCD is the sum of the areas of two triangles: a right triangle ABD and a scalene triangle CDB.

We will determine the area of each triangle individually and then sum their values.

Right Triangle ABD:

We can use the above area formula if we know the angle between two sides.

Looking at our triangle, we know that ∠ADB is 55 DB is 10.

So, if we can find AD, we can apply the formula.

Notice that AD is the adjacent side to ∠ADB. Also, DB is the hypotenuse.

Since this is a right triangle, we can utilize the trig ratios.

In this case, we will use cosine. Remember that cosine is the ratio of the adjacent side to the hypotenuse.

Therefore:

\displaystyle \cos(55)=\frac{AD}{10}

Solve for AD:

AD=10\cos(55)

Now, we can use the formula. We have:

\displaystyle A=\frac{1}{2}ab\sin(C)

Substituting AD for a, 10 for b, and 55 for C, we get:

\displaystyle A=\frac{1}{2}(10\cos(55))(10)\sin(55)

Simplify. Therefore, the area of the right triangle is:

A=50\cos(55)\sin(55)

We will not evaluate this, as we do not want inaccuracies in our final answer.

Scalene Triangle CDB:

We will use the same tactic as above.

We see that if we can determine CD, we can use our area formula.

First, we can determine ∠C. Since the interior angles sum to 180 in a triangle, this means that:

\begin{aligned}m \angle C+44+38&=180 \\m\angle C+82&=180 \\ m\angle C&=98\end{aligned}

Notice that we know the angle opposite to CD.

And, ∠C is opposite to BD, which measures 10.

Therefore, we can use the Law of Sines to determine CD:

\displaystyle \frac{\sin(A)}{a}=\frac{\sin(B)}{b}

Where A and B are the angles opposite to its respective sides.

So, we can substitute 98 for A, 10 for a, 38 for B, and CD for b. Therefore:

\displaystyle \frac{\sin(98)}{10}=\frac{\sin(38)}{CD}

Solve for CD. Cross-multiply:

CD\sin(98)=10\sin(38)

Divide both sides by sin(98). Hence:

\displaystyle CD=\frac{10\sin(38)}{\sin(98)}

Therefore, we can now use our area formula:

\displaystyle A=\frac{1}{2}ab\sin(C)

We will substitute 10 for a, CD for b, and 44 for C. Hence:

\displaystyle A=\frac{1}{2}(10)(\frac{10\sin(38)}{\sin(98)})\sin(44)

Simplify. So, the area of the scalene triangle is:

\displaystyle A=\frac{50\sin(38)\sin(44)}{\sin(98)}

Therefore, our total area will be given by:

\displaystyle A_{\text{Total}}=50\cos(55)\sin(55)+\frac{50\sin(38)\sin(44)}{\sin(98)}

Approximate. Use a calculator. Thus:

\displaystyle A_{\text{Total}}\approx45.0861\approx45.1

8 0
3 years ago
5-x&lt;8;x=-3 how do you solve that?
Sergio [31]
Make sure you substitute x for 3

The equation would be:

5-3<8

Subtract 3

2<8

The statement is true
8 0
3 years ago
The expression 60(0.75)^x represents the amount of a drug in milligrams that remains in the bloodstream after x hour. What was t
kogti [31]
It would be 60.

a(b)^x
Since a/ 60 would represent initial value.
7 0
3 years ago
Kelly has 6 sheets of stickers, with 9 stickers on each sheet. Her aunt gives her 5 more sheets, with 10 stickers on each sheet.
NemiM [27]
104. 54+50. 6 times 9 equals 54. Ten times 5 equals 50.
8 0
3 years ago
What is the quotient?
Ierofanga [76]

Answer:

3/2

Step-by-step explanation:

For dividing rational expressions such as the one given, we use the same concept that we use when dividing fractions.

Thus, we multiply the first expression with the second expression's reciprocal as shown below.

\frac{2m + 4}{8}   \div  \frac{m + 2}{6}

\frac{2(m + 2)}{8}  \times  \frac{6}{m + 2}

We can cancel common factors and simplify the product. Hence, we have

\frac{2(6)}{8}

\frac{3}{2}

Therefore, the quotient of the expressions is equal to 3/2.

6 0
2 years ago
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