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kobusy [5.1K]
3 years ago
15

If y= x+3/6-x, what is the value of y when x =7i?

Mathematics
1 answer:
djverab [1.8K]3 years ago
3 0

Answer:

Option (2)

Step-by-step explanation:

Given :  y = \frac{x+3}{6-x}

If x = 7i

y = \frac{7i+3}{6-7i}

By simplifying denominator of the given rational expression,

y = \frac{7i+3}{6-7i}\times \frac{6+7i}{6+7i}

y = \frac{(7i+3)(6+7i)}{6^2-(7i)^2}

y = \frac{7i(6+7i)+3(6+7i)}{36-49i^2}

y = \frac{42i+49i^2+18+21i}{36+49} [Since, i² = (-1)]

y = \frac{63i-49+18}{85}

y = \frac{63i-31}{85}

y = -\frac{31}{85}+\frac{63}{85}i

Therefore, Option (2) is the correct option.

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A batch of snack mix made of dried fruit and nuts contain 744G of nuts the ratio of nuts to dried fruit by weight is 12 to 13 ho
Bezzdna [24]

In a bag of snack mix:

n = nuts       d = dried fruit

n = 744g        d = ???g

Ratio Nuts/Dried fruit = 12/13

This basically means that if the mix was divided in 25 parts, 12 parts would be nuts and 13 would be dried fruits

If 744 is 12 parts then 744/12 is 1 part

744/12 = 62

1 part = 62g

there are 13 parts of dried fruit

13 x 62 = 806

744g of nuts + 806g of dreid fruit = 1550g

Answer: A batch of snack mix weigh 1550g, or 1.55kg

hope it helps :)

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