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vesna_86 [32]
4 years ago
12

We will flip a balanced coin 3 times and for each toss, record whether we get a Head or a Tail. Write all possible outcomes of t

his experiment to find the probability that we get exactly 2 heads. Group of answer choices
Mathematics
1 answer:
VMariaS [17]4 years ago
4 0

Answer:

probability to get exactly 2 heads when flipped a balanced coin 3 times is 3/8 = 0.375 (37.5%)

Step-by-step explanation:

Denoting H as head and T as tails , then in 3 flips there are 2³=8 possible outcomes.

the possible outcomes in 3 flips are

H , H , H

H , H , T

H , T , H

H , T , T

T , H , H

T , H , T

T , T , H

T , T , T

then there are 3 outcomes out of 8 where there are exactly 2 heads ( 2 heads with the tails in the 3 different places possible)

then the probability to get exactly 2 heads when flipped a balanced coin 3 times is 3/8 = 0.375 (37.5%)

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7 0
4 years ago
Need help asap for test
alex41 [277]

Answer:

a=4 and b=-1

Step-by-step explanation:

2(4)+3(-1)= 5

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Answer please. If you answer, you get 44 points. I don't use the points here. So answer please. I want full work.
ra1l [238]

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Step-by-step explanation:

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3 years ago
Read 2 more answers
A factory makes 640brushes in 4 hours.Does the equation y=150x model the number of brushes made each hour?
adelina 88 [10]

Answer:

No it doesn't

Step-by-step explanation:

The equation we have is

Y = 150x

We have x = 4 hours

This is a simple question. We have to plug in the x = 4 in the equation to find out if we would have 640 brushes. If y = 640, then it models it. But if y is not equal to 640, it doesn't.

So let's solve this to see for ourselves.

Y = 150(x)

We put the value of x

Y = 150(4)

Y = 600

So we can see that the equation does not model the number of brushes made each hour. This equation models 600 brushes and not 640.

7 0
3 years ago
You have a bag of 12 marbles. Four are blue, 6 are green, 2 are red, and the others are yellow. What is the probability of drawi
8090 [49]

Answer:

Probability = \frac{1}{11}

Step-by-step explanation:

Given

Blue = 4

Green = 6

Red = 2

Total = 12

Required

Determine the probability of drawing red and green without replacement

This is calculated as follows:

Probability = P(Red\ and\ Green)

Probability = P(Red)\ and\ P(Green)

Probability = \frac{n(Red)}{Total} * \frac{n(Green)}{Total - 1}

We used Total - 1 because it's a probability without replacement:

Probability = \frac{2}{12} * \frac{6}{12- 1}

Probability = \frac{2}{12} * \frac{6}{11}

Probability = \frac{1}{6} * \frac{6}{11}

Probability = \frac{1}{11}

<em>Hence, the required probability is 1/11</em>

5 0
3 years ago
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