-4x+y=6
y=4x+6
-x=3
y=4(-3)+6
y=-6
therefore, y=-6, x=-3
True.
Let p1 and p2 be the two parallel planes. Let n1 be the normal vector of plane p1 (which is a vector perpendicular to the plane). If p2 is parallel to p1, then n1 is also a normal vector for p2.
Let p3 be the third secant plane, and n3 be its normal vector.
The direction vector of the intersection line of two planes is given by the cross products of their normal vectors (this is due to the fact that the cross product of two vectors is orthogonal two both of them, and that the direction vector of the intersection must be orthogonal two both normal vectors). So, the direction vectors of the two lines are:
v1 = n1 × n3
v2 = n1 × n3
The are equal. Hence, the lines are parallel.
Answer:
Step-by-step explanation:
we know that
Applying the Pythagoras Theorem
In this problem we have that
substitute
The first term is 7, and the common difference is 4. We know this because 11-7=15-11=4. So the nth term is going to be 7+4(n-1). The 26th term will be 7+4(26-1)=7+100=107. The sum of the series is going to be (107+7)*13=1482.
Answer:
The number of cars that brings the same profit is 9 and 0
Step-by-step explanation:
Given
Required
Determine the possible values of x
Subtract 5x from both sides
Factorize
Split the equation
or 
or 
<em>Hence, the number of cars that brings the same profit is 9 and 0</em>
