Solve 5x − 6y = −38 <br> 3x + 4y = 0

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

Another Math Problem.

Xelga [282]

For part A Amy's estimate is inaccurate because when adding fractions they must have the same denominators. Amy probably made the mistake of adding 1/4 and 1/3 without changing the denominators first which gave her 1/7. If she were to do it correctly then she would've ended up with 7/12 as her answer.

My work:

1/4=3/12
1/3=4/12
4/12+3/12=7/12

I hope this helps and if I gave any false information I apologize in advance.

5 0

3 years ago

Products of polynomials <br> Find the product,please. <br> (4a-ts)(2a+2ts)

gregori [183]

Answer:

(4a + 2)3

Step-by-step explanation:

(4a + 2)(4a + 2)(4a + 2) multliply first two with FOIL

(16a2 +16a + 4)(4a + 2) multiply these using distributive

16a2(4a) + 16a(4a) + 4(4a) + 16a2(2) + 16a(2) + 4(2)

64a3 + 64a2 + 16a + 32a2 + 32a + 8

64a3 + 96a2 + 48a + 8

4 0

4 years ago

Suppose you have 9 tubes of paint. How many distinct color groupings can you make with your paint?

alexdok [17]

9514 1404 393

Answer:

511

Step-by-step explanation:

Each tube can be included in the mix, or not. There are 2^9 = 512 possible subsets of a set of 9 objects, including the complete set and the empty set. The empty set will not make a color, so there are ...

2^9 - 1 = 511 distinct color groupings that can be made

__

The assumption in the above answer is that no tube color can be made by any combination of other tube colors.* We also assume that the choice of tubes is what makes a "color grouping", and that the colors within that grouping made by using different ratios of paint quantities are not counted separately.

7 0

3 years ago

ESTI

castortr0y [4]

Answer:

What?

Step-by-step explanation:

3 0

3 years ago

Solve 5x − 6y = −38 3x + 4y = 0