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natulia [17]
4 years ago
14

Which of the following is an example of batch processing?

Computers and Technology
1 answer:
9966 [12]4 years ago
7 0

Answer:

several personnel accessing the registration system

Explanation:

batch processing is all about multiprogramming so I think the first answer is the best as it is not based on one person .I know the last answer might be almost close but on a closer look it is not the answer as it is single based as written a file

You might be interested in
Write a program in C which will open a text file named Story.txt. You can create the file using any text editor like notepad etc
ddd [48]

Answer:

See explaination

Explanation:

#include <stdio.h>

#include <stdlib.h>

int main()

{

FILE * file_object;

char file_name[100];

char ch;

int characters=0, words=0;

printf("Enter source file name: ");

scanf("%s", file_name); //asking user to enter the file name

file_object = fopen(file_name, "r"); //open file in read mode

if (file_object == NULL)

{

printf("\nUnable to open file.file not exist\n"); //check if the file is present or not

}

while ((ch = fgetc(file_object)) != EOF) //read each character till the end of the file

{

if (ch == ' ' || ch == '\t' || ch == '\n' || ch == '\0') //if character is space or tab or new line or null character increment word count

words++;

else

characters++; //else increment character count this assures that there is no spaces count

}

printf("The file story.txt has the following Statistics:\n"); //finally print the final statistics

if (characters > 0)

{

printf("Words: %d\n", words+1); //for last word purpose just increment the count of words

printf("Characters (no spaces): %d\n", characters);

}

fclose(file_object); //close the file object

return 0;

}

6 0
4 years ago
8.17 Lab: Strings of a Frequency Write a program that reads whitespace delimited strings (words) and an integer (freq). Then, th
WITCHER [35]

Answer:

def wordsOfFreqency(words, freq):

 text1 = "Apple apPLE mangO aPple orange Orange apple guava Mango mango"

 words = []

 words1 = []

 words1 = text1.split()

 words = [x.upper() for x in words1]

 freq=[words.count(w) for w in words]

 print(dict(zip(freq,words)))

 return words

def main():

wordsOfFreqency(words, freq)      

if __name__=="__main__":

main()    # call main function

Explanation:

This will print the list of strings as per its word frequency.

Output is :

{4: 'APPLE', 3: 'MANGO', 2: 'ORANGE', 1: 'GUAVA'}

4 0
3 years ago
Complete the sentence to identify advantages of top-down programming design. Choose all that apply.
yanalaym [24]

Answer:The original choice to write apply_fg so that it accepts function arguments is a good one, because it increases interoperability. When the callable arguments to apply_fg use a single protocol, we can easily exchange them: #include <functional> float log2(float); int a = apply_fg(5.Of, int b = apply_fg(3.14f,

Explanation:

3 0
4 years ago
Read 2 more answers
David bought 5.2 pounds of oranges for $1.20 per pound . how much did david spend ..............................................
Tcecarenko [31]

Answer:

David spent $6.24.

Explanation:

5.2 times 1.2

3 0
3 years ago
Write a program to sort an array of 100,000 random elements using quicksort as follows: Sort the arrays using pivot as the middl
Stels [109]

Answer:

Check the explanation

Explanation:

#include<iostream.h>

#include<algorithm.h>

#include<climits.h>

#include<bits/stdc++.h>

#include<cstring.h>

using namespace std;

int partition(int arr[], int l, int r, int k);

int kthSmallest(int arr[], int l, int r, int k);

void quickSort(int arr[], int l, int h)

{

if (l < h)

{

// Find size of current subarray

int n = h-l+1;

 

// Find median of arr[].

int med = kthSmallest(arr, l, h, n/2);

 

// Partition the array around median

int p = partition(arr, l, h, med);

 

// Recur for left and right of partition

quickSort(arr, l, p - 1);

quickSort(arr, p + 1, h);

}

int findMedian(int arr[], int n)

{

sort(arr, arr+n); // Sort the array

return arr[n/2]; // Return middle element

}

int kthSmallest(int arr[], int l, int r, int k)

{

// If k is smaller than number of elements in array

if (k > 0 && k <= r - l + 1)

{

int n = r-l+1; // Number of elements in arr[l..r]

 

// Divide arr[] in groups of size 5, calculate median

// of every group and store it in median[] array.

int i, median[(n+4)/5]; // There will be floor((n+4)/5) groups;

for (i=0; i<n/5; i++)

median[i] = findMedian(arr+l+i*5, 5);

if (i*5 < n) //For last group with less than 5 elements

{

median[i] = findMedian(arr+l+i*5, n%5);

i++;

}

int medOfMed = (i == 1)? median[i-1]:

kthSmallest(median, 0, i-1, i/2);

int pos = partition(arr, l, r, medOfMed);

if (pos-l == k-1)

return arr[pos];

if (pos-l > k-1) // If position is more, recur for left

return kthSmallest(arr, l, pos-1, k);

return kthSmallest(arr, pos+1, r, k-pos+l-1);

}

return INT_MAX;

}

void swap(int *a, int *b)

{

int temp = *a;

*a = *b;

*b = temp;

}

int partition(int arr[], int l, int r, int x)

{

// Search for x in arr[l..r] and move it to end

int i;

for (i=l; i<r; i++)

if (arr[i] == x)

break;

swap(&arr[i], &arr[r]);

 

// Standard partition algorithm

i = l;

for (int j = l; j <= r - 1; j++)

{

if (arr[j] <= x)

{

swap(&arr[i], &arr[j]);

i++;

}

}

swap(&arr[i], &arr[r]);

return i;

}

 

/* Function to print an array */

void printArray(int arr[], int size)

{

int i;

for (i=0; i < size; i++)

cout << arr[i] << " ";

cout << endl;

}

 

// Driver program to test above functions

int main()

{

float a;

clock_t time_req;

int arr[] = {1000, 10, 7, 8, 9, 30, 900, 1, 5, 6, 20};

int n = sizeof(arr)/sizeof(arr[0]);

quickSort(arr, 0, n-1);

cout << "Sorted array is\n";

printArray(arr, n);

time_req = clock();

for(int i=0; i<200000; i++)

{

a = log(i*i*i*i);

}

time_req = clock()- time_req;

cout << "Processor time taken for multiplication: "

<< (float)time_req/CLOCKS_PER_SEC << " seconds" << endl;

 

// Using pow function

time_req = clock();

for(int i=0; i<200000; i++)

{

a = log(pow(i, 4));

}

time_req = clock() - time_req;

cout << "Processor time taken in pow function: "

<< (float)time_req/CLOCKS_PER_S

return 0;

}

..................................................................................................................................................................................................................................................................................................................................

OR

.......................

#include <stdio.h>

#include <stdlib.h>

#include <time.h>

 

// Swap utility

void swap(long int* a, long int* b)

{

int tmp = *a;

*a = *b;

*b = tmp;

}

 

// Bubble sort

void bubbleSort(long int a[], long int n)

{

for (long int i = 0; i < n - 1; i++) {

for (long int j = 0; j < n - 1 - i; j++) {

if (a[j] > a[j + 1]) {

swap(&a[j], &a[j + 1]);

}

}

}

}

 

// Insertion sort

void insertionSort(long int arr[], long int n)

{

long int i, key, j;

for (i = 1; i < n; i++) {

key = arr[i];

j = i - 1;

 

// Move elements of arr[0..i-1], that are

// greater than key, to one position ahead

// of their current position

while (j >= 0 && arr[j] > key) {

arr[j + 1] = arr[j];

j = j - 1;

}

arr[j + 1] = key;

}

}

 

// Selection sort

void selectionSort(long int arr[], long int n)

{

long int i, j, midx;

 

for (i = 0; i < n - 1; i++) {

 

// Find the minimum element in unsorted array

midx = i;

 

for (j = i + 1; j < n; j++)

if (arr[j] < arr[min_idx])

midx = j;

 

// for plotting graph with integer values

printf("%li, %li, %li, %li\n",

n,

(long int)tim1[it],

(long int)tim2[it],

(long int)tim3[it]);

 

// increases the size of array by 10000

n += 10000;

}

 

return 0;

}

8 0
4 years ago
Read 2 more answers
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