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Oliga [24]
3 years ago
11

A network is a group of two or more computers or devices connected together. To be able to connect, they each need a

Computers and Technology
2 answers:
Kay [80]3 years ago
6 0
D. Internet service protocol (isp)
nasty-shy [4]3 years ago
5 0
<span>D. Internet Service Protocol (ISP)</span>
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Identify 5 internal and external hardware components of a server
UNO [17]

Answer:

Internal:

#CPU; That retrieves &execute instructions.

#Modem; Modulates& demodulates electric signals.

#RAM;Gives application a place to store &access data on a short time periods.

External:

#Mouse; Transmits commands and controlling movements.

#Moniter; Device used to display video output from computer.

#Printer; Accepts text, graphics to the paper.

Explanation:

Hope this will help you.

5 0
3 years ago
Timeliness is an important goal of any access control monitoring system.<br> A. True<br> B. False
Damm [24]
The answer for this question is true
7 0
4 years ago
¿Cuales son las empresas mas exitosas que aún usan hoja de cálculo? porfa es urgentee
dem82 [27]

Answer:excel

Explanation:

6 0
3 years ago
If you are installing separate anti-virus and anti-spyware programs, which should you install first
Vera_Pavlovna [14]
Probably the anti virus, so you don't get a virus from downloading the anti spyware program.
6 0
3 years ago
Finish and test the following two functions append and merge in the skeleton file:
avanturin [10]

Answer:

Explanation:

#include <iostream>

using namespace std;

int* append(int*,int,int*,int);

int* merge(int*,int,int*,int);

void print(int*,int);

int main()

{ int a[] = {11,33,55,77,99};

int b[] = {22,44,66,88};

print(a,5);

print(b,4);

int* c = append(a,5,b,4); // c points to the appended array=

print(c,9);

int* d = merge(a,5,b,4);

print(d,9);

}

void print(int* a, int n)

{ cout << "{" << a[0];

for (int i=1; i<n; i++)

cout << "," << a[i];

cout << "}\n";

}

int* append(int* a, int m, int* b, int n)

{

int * p= (int *)malloc(sizeof(int)*(m+n));

int i,index=0;

for(i=0;i<m;i++)

p[index++]=a[i];

for(i=0;i<n;i++)

p[index++]=b[i];

return p;

}

int* merge(int* a, int m, int* b, int n)

{

int i, j, k;

j = k = 0;

int *mergeRes = (int *)malloc(sizeof(int)*(m+n));

for (i = 0; i < m + n;) {

if (j < m && k < n) {

if (a[j] < b[k]) {

mergeRes[i] = a[j];

j++;

}

else {

mergeRes[i] = b[k];

k++;

}

i++;

}

// copying remaining elements from the b

else if (j == m) {

for (; i < m + n;) {

mergeRes[i] = b[k];

k++;

i++;

}

}

// copying remaining elements from the a

else {

for (; i < m + n;) {

mergeRes[i] = a[j];

j++;

i++;

}

}

}

return mergeRes;

}

4 0
4 years ago
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