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4 years ago

Solve for x. x^2−3x=10

Mathematics

2 answers:

CaHeK987 [17]4 years ago

4 0

Answer:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

x=5,−2

Step-by-step explanation:

I can do math

Alisiya [41]4 years ago

4 0

Answer: x = 5, -2

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

The perimeter of this triangle is 46cm find x

notka56 [123]

Answer:

the value of x is 12

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2 years ago

Find the equation of the line tangent to y = -3x2 + x - 5 at x = -1

SVEN [57.7K]

$\boxed{y+9=7(x+1)}$

<h2>Explanation:</h2>

The Point-Slope form of the equation of a line is given by:

$y-y_{0}=m(x-x_{0}) \\ \\ \\ Where: \\ \\ m:Slope \\ \\ (x_{0},y_{0}):A \ point$

To find the equation of the line tangent to $y=-3x^2+x-5 \ at \ x=-1$ , we need to take the derivative:

$\frac{dy}{dx}=-6x+ 1$

The slope of the line tangent to $y=-3x^2+x-5$ at $x=-1$ can be found evaluationg $x=1$ in the derivative:

$\frac{dy}{dx}\Bigr\rvert_{x=-1}=-6x+ 1 \\ \\ \\ \frac{dy}{dx}\Bigr\rvert_{x=-1}=-6(-1)+ 1 \\ \\ \\ m=\frac{dy}{dx}\Bigr\rvert_{x=-1}=7$

Finding the point:

$x_{0}=-1 \\ \\ Then: \\ \\ y_{0}=-3(-1)^2-1-5=-9 \\ \\ (x_{0},y_{0})=(-1,-9)$

Finally, our line is:

$y-(-9)=7(x-(-1)) \\ \\ \boxed{y+9=7(x+1)}$

The representation of this problem is shown below.

<h2>Learn more:</h2>

Derivative of functions: brainly.com/question/2142425

#LearnWithBrainly

6 0

3 years ago

A rectangle has an area of x^3+x^2-7x+2 square meters and a width of x-2 meters. Find its length.

gladu [14]

$\bf \textit{area of a rectangle}=A=length\times width\implies \cfrac{A}{width}=length
\\\\\\
thus\quad 
\begin{cases}
A=x^3+x^2-7x+2\\
width=x-2
\end{cases}\implies \cfrac{x^3+x^2-7x+2}{x-2}=length$

hint: divisor is x-2 form, thus you can use syntheric division

5 0

3 years ago

Multiplies to -4<br> Adds to o

nikklg [1K]

-2 times 2 equals -4 and if you add them it equals 0

4 0

3 years ago