Answer: 0.139
Step-by-step explanation:
From the given table, the total number of females = 252. The number of females that owned cats = 35. Therefore , the relative frequency of women that owned cats is given by -
Number of females that own cats/ Number of females
= 35/252 = 0.138888888889 = 0.139
Therefore, the relative frequency of women that owned cats is 0.139.
They could have travelled any distance. In total, they travelled 1.75 times the distance of the first day, but since we do not know the distance of the first day, we have no idea the actual distance. For all we know they could have gone to the moon in the first day.
0,1
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Answer:
7x-4y=-8.........(i)
y=3/4x-3........(ii)
Putting the value of y in eqn(i)
7x-4y=-8
or, 7x-4(3/4x-3)=-8
or, 7x-3x+12=-8
or, 4x=-8-12
or, x=-20/4
x=-5
again,
putting the value of x in eqn(ii)
y=3/4x-3
y=-5(3/4) -3
y=-15/4 -3
y=-3/4
x=-5
y=-3/4
It is B because have you do 160+77-x=180 you would add the like terms 160+77=237 and then subtract 180 from 237 and you get 57 for x and when you plug that in 160+77-57 77-57=20 and 20 plus 160 is 180 so The answer is B)No of these