Factor each expression 77x+21

1 answer:

4 0

77x + 21

We need to find the common factor between the coefficient and the constant.

77 ÷ 7 = 11
21 ÷ 7 = 3

7(11x + 3) is the factor of 77x + 21.

7(11x + 3) can be expanded using the distributive property of multiplication.

7(11x) + 7(3) = 77x + 21

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A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. The

Delvig [45]

10 small boxes and 11 large boxes were shipped.

Step-by-step explanation:

Given,

Total boxes shipped = 21

Total volume of shipped boxes = 342 cubic feet

Volume of each small box = 10 cubic feet

Volume of each large box = 22 cubic feet

Let,

Number of small boxes = x

Number of large boxes = y

According to given statement;

x+y=21 Eqn 1

10x+22y=342 Eqn 2

Multiplying Eqn 1 by 10

$10(x+y=21)\\10x+10y=210\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(10x+22y)-(10x+10y)=342-210\\10x+22y-10x-10y=132\\12y=132$

Dividing both sides by 12

$\frac{12y}{12}=\frac{132}{12}\\y=11$

Putting y=11 in Eqn 1

$x+11=21\\x=21-11\\x=10$

10 small boxes and 11 large boxes were shipped.

Keywords: linear equation, subtraction

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3 0

3 years ago

I need help ASAP. If TU=10 and ST=15, What is the measure of the radius of the circle?

Svetach [21]

Answer:

5.6

Step-by-step explanation:

Use pythag to get SU. 10^2 + x^2 = 15^2, this will give you x = 11.2. 11.2 is the diameter of SU so divide it by 2 to get the radius. 11.2/2= 5.6.

3 0

2 years ago

A regular hexagon is inscribed in a circle as shown determine the measure of FE

Ostrovityanka [42]

The complete question in the attached figure

we know that
1) <span>The triangles that are formed in the hexagon by joining all the vertices with the center of the hexagon are all equilateral and are equal in size
therefore
the radius of the circle is equals to the length side of the regular hexagon
FE=BP--------> FE=6 cm

the answer is
FE=6 cm </span>