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Elenna [48]
4 years ago
9

Why is it essential to know what information will be needed from the database from the outset of development?

Computers and Technology
1 answer:
KIM [24]4 years ago
7 0

Answer:

all of the answers

Explanation:

According to my research on information technology, I can say that based on the information provided within the question all of the answers provided would be important pieces of information to know. This is because each provides information on another and all information possible is helpful in a development process.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Answer: B webcast

Explanation:

A webcast is a technology that allows the live broadcast of an audio or video event on the Internet. It is also known as Web lecture, virtual meeting, etc. The major advantage is that it gives room for an event to have a larger reach. Webcast participation can be through PC, smart phones, tablets and other devices with quality Internet access.

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4 years ago
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In a stack, if a user tries to remove an element from an empty stack it is called.
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In a stack, if a user tries to remove an element from an empty stack it is called underflow.

<h3>What is underflow?</h3>

When we attempt to pop (remove) anything off the stack but there is nothing there to remove, stack underflow occurs. The computer will kind of sound an alert as a result of what we taught it to do, which is impossible.

The options are:

1) Underflow

2) Empty collection

3) Overflow

4) Garbage collection

As we know,

When an item is requested from the stack but the stack is empty, an error situation arises.

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2 years ago
Describe a problem you’ve solved or a problem you’d like to solve. It can be an intellectual challenge, a research query, an eth
iogann1982 [59]

Answer:

Explanation:

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What is the definition of assiduous?
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Answer:

showing great care and perseverance.

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3 years ago
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First, launch NetBeans and close any previous projects that may be open (at the top menu go to File ==&gt; Close All Projects).
Mars2501 [29]

Answer:

See explaination

Explanation:

// LetterCount.java

import java.io.File;

import java.io.IOException;

import java.io.PrintWriter;

import java.util.NoSuchElementException;

import java.util.Scanner;

public class LetterCount {

public static void main(String[] args) {

// setting up a Scanner to read from keyboard

Scanner scanner = new Scanner(System.in);

try {

// asking and reading input file name

System.out.print("Enter name of input file: ");

String file = scanner.nextLine();

// reinitializing scanner to read from input file. this will throw

// file not found exception if file is not found.

scanner = new Scanner(new File(file));

// opening a file writer to create and write into output.txt file

PrintWriter writer = new PrintWriter(new File("output.txt"));

// creating a String containing all 26 alphabets

String alphabet = "abcdefghijklmnopqrstuvwxyz";

// creating an array containing 26 integers, all initialized to 0

int counts[] = new int[26];

// looping through the file

while (scanner.hasNext()) {

// reading next line, converting to lower case

String word = scanner.next().toLowerCase();

// looping through each character in current word

for (char c : word.toCharArray()) {

// finding index of c in alphabet

int index = alphabet.indexOf(c);

// if c is an alphabet, the index value will not be -1

if (index != -1) {

// incrementing counter at index position

counts[index]++;

}

}

}

// closing input file

scanner.close();

int largestCount = 0; // to store largest count of a character

String mostCommon = ""; // to store the character(s) that occur the

// most

// looping through counts array, finding the largest value

for (int i = 0; i < counts.length; i++) {

if (counts[i] > largestCount) {

// updating largestCount and mostCommon

largestCount = counts[i];

mostCommon = alphabet.charAt(i) + "";

} else if (counts[i] == largestCount) {

// same largest count, appending to mostCommon string

mostCommon += " " + alphabet.charAt(i);

}

}

// writing results to output file

writer.println("The most common letter(s): " + mostCommon);

writer.println("Count of occurrances: " + largestCount);

// closing file, saving changes, alerting user

writer.close();

System.out

.println("done! please check output.txt file for results.");

} catch (IOException e) {

// will be executed when the input/output file cant be opened or

// found, or if there is an error while reading the file

System.out.println(e.getMessage());

} catch (NoSuchElementException e) {

// will occur when there is no input provided for input file name.

System.out.println("No input!");

}

}

}

8 0
3 years ago
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