it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.
Let h(t) represent the height of the ball at time t.
Given that the height is given by:
h(t) = -16t² + 80t + 40
1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:
40 = -16t² + 80t + 40
16t² - 80t = 0
t(t - 5) = 0
t = 0 or t = 5
Hence it takes 5 seconds to reach a height of 40 ft.
2) The maximum height is at h'(t) = 0,
h'(t) = -32t + 80
-32t + 80 = 0
32t = 80
t = 2.5
It takes 2.5 seconds to reach maximum height.
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Answer:
40 steps downwards
Step-by-step explanation:
Answer:
Step-by-step explanation:
The answer would be to find the LCM of both 3 and 5, which is 15. The 15th customer would receive both a mug and a t-shirt. Let's call mugs "x" and shirts "o" and line them up. The bold x's and o's are the lucky winners:
x x x x x x x x x x x x x x x
o o o o o o o o o o o o o o o
The last x and the last o are both bold for the first time right there, at the 15th letter of each.
MNOP is similar to QRST with ratio of 5:4<span>. That means the MP:QT ratio would also be 5:4
The length of QT would be
</span>MP/QT = 5/4<span>
85mm/QT=5/4
85mm*4= 5*QT
5QT= 340
QT=68mm</span>
Answer:
Step-by-step explanation:
C=(tx3)
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