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Paraphin [41]
3 years ago
5

Could someone please help. The given sides are 25 at the left, 35 at bottoms, 5 at the right. Thank you :)

Mathematics
1 answer:
NeTakaya3 years ago
6 0

Answer:

120 cm

Step-by-step explanation:

If you rearrange the lines you will get a rectangle whose sides are 25 cm and 35 cm.

To get a triangle, move the lines inside the rectangle keeping them parallel to the lines in front of them.

Let P the perimeter of the rectangle:

P = 25*2 + 35*2 = 50+70 = 120 cm

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Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
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Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

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The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

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We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

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