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damaskus [11]
3 years ago
8

It has been estimated that as many as 70% of the fish caught in certain areas of the Great Lakes have liver cancer due to the po

llutants present. Find an approximate 95% range for the percentage of fish with liver cancer present in a sample of 130 fish.
Mathematics
1 answer:
Likurg_2 [28]3 years ago
7 0

Answer:

62.12% to 77.88%

Step-by-step explanation:

We proceed as follows mathematically;

From the question

n=130

Estimate for sample proportion=70% = 70/100 = 0.7 = p

Level of significance is =1-0.95=0.05

Z critical value(using Z table)=1.96

Confidence interval formula is ;

p ± Z * √(p(1-p)/n

= 0.70 ± √(0.7(1-0.7)/130

=(0.6212,0.7788)

Lower confidence interval limit =0.6212

Upper confidence interval limit =0.7788

In percentages , we simply multiply by 100 in both cases =

62.12 % to 77.88%

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Answer:

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Suppose each runner ran at the rate given in the table above for 3.1 miles. How much time will elapse between the first place fi
Scilla [17]
You didn't include the table but I found this table for the same statement, so I will answer you based on the next table:

Runner         distance           time

Arabella        7,299 feet        561 seconds
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First you need to convert the data to obtain the rate in miles per second.

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1 hour = 3600 seconds

1 hour = 60 minutes

1 minute = 60 seconds

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Time = 3.1 mile / 0.00222 seconds = 0.389 hour = 1396 seconds

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rate = 1.62 miles / 732 seconds = 0.00221 seconds

Time = 3.1 mile / 0.00221 seconds = 1403 seconds

Now you can find the difference between fhe last and the first 1403 seconds - 1260 seconds = 143 seconds

That is equivalent to 2.38 seconds.
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