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3 years ago

Let f(x)=-5x-4 and g(x)=6x-7. find f(x) + g(x)

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

6 0

Answer:Unit 2 Lesson 6 Function Operations

1. D x - 11

2. B -3x + 9 Don't get confused with the - 7, since you are subtracting 3x + 2 - 6x - 7, the - 7 switches to + 7.

3. C -30x^2 + 28x - 6; all real numbers

4. D x - 4; all real numbers except x /= -4

5. C It doesn't matter which discount is applied first, the result will be the same.

100% correct, cheers!

Step-by-step explanation:

DIA [1.3K]3 years ago

3 0

F(x) = -5x - 4

g(x) = 6x - 7

f(x) + g(x) = (-5x-4) + (6x-7)

f(x) + g(x) = x - 11

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What is the outlier of the data set 7, 15, 15, 15, 13, 7, 9, 11, 24

eduard

Answer:

Step-by-step explanation:

The outlier is the value that is far from the other values in the set

24 is far from the other values

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3 years ago

What is 40 percent of 90 percent

Brums [2.3K]

Answer:0.36

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2 years ago

Alexander is building a rectangular pen in his backyard for his dog. The pen will have a length of 13 feet and a width of 2x fee

Drupady [299]

4x+26

Step-by-step explanation:

to buy fencing, you need to find the perimeter of the pen. The perimeter is found by adding all sides together.

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2 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al

Furkat [3]

Answer: $\frac{\sqrt[4]{10xy^3}}{2y}$

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

$\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\$

The idea is to get something of the form $a^4$ in the denominator. In this case, $a = 2y$

To be able to reach the $16y^4$ , your teacher gave the hint to multiply top and bottom by $2y^3$

For more examples, search out "rationalizing the denominator".

Keep in mind that $\sqrt[4]{(2y)^4} = 2y$ only works if y isn't negative.

If y could be negative, then we'd have to say $\sqrt[4]{(2y)^4} = |2y|$ . The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0

2 years ago

Find the largest prime divisor of $15^6 - 7^6$<img src="https://tex.z-dn.net/?f=Find%20the%20largest%20prime%20divisor%20of%20%2

Novosadov [1.4K]

Answer:

Largest prime factor of the given expression is <em>379.</em>

Step-by-step explanation:

Given the expression:

$15^6 - 7^6$

To find:

The largest prime factor of the given expression.

Solution:

First of all, let us factorize the given expression.

$15^6 - 7^6\\\Rightarrow (15^3)^2 - (7^3)^2\\\\\text{Using } x^{2} -y^2 = (x+y) (x-y)\\\\\Rightarrow (15^3+7^3)(15^3-7^3)$

Let us learn two formula:

$x^3+y^3 = (x+y)(x^2+y^2-xy)$

$x^3-y^3 = (x-y)(x^2+y^2+xy)$

Applying the above formula in the expression written above:

$(15^3+7^3) = (15+7)(15^2+7^2-15\times 7)\\\Rightarrow 22(225+49-105 ) = 2 \times 11 \times 169 \\\Rightarrow 2 \times 11\times 13\times 13\\\Rightarrow 2 \times 11\times 13^2$ ...... (1)

Similarly:

$(15^3-7^3) = (15-7)(15^2+7^2+15\times 7)\\\Rightarrow 8(225+49+105 ) = 2^3 \times 379$ ........ (2)

Multiplying the expressions from (1) and (2) to get the result:

$\therefore 15^6 - 7^6 = 2^4 \times 11 \times \underline{\bold{379}} \times 13 ^2$

So, largest prime factor of the given expression is <em>379.</em>

7 0

3 years ago