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Andre45 [30]
2 years ago
15

Find the average rate of change of the function from x=1 to x=2.

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
5 0

Answer:

Average rate of change = \frac{15}{2}

Step-by-step explanation:

For a closed interval [a,b] in a function, the average rate of change is m=\frac{f(b)-f(a)}{b-a}.

Thus, given our interval of [1,2] from the directions, we determine that f(b)=f(2)=-\frac{10}{(2)^2}=-\frac{10}{4}=-\frac{5}{2} and f(a)=f(1)=-\frac{10}{(1)^2}=-\frac{10}{1}=-10.

Hence, m=\frac{f(b)-f(a)}{b-a}=\frac{(-\frac{5}{2})-(-10) }{2-1}=\frac{\frac{15}{2}}{1}=\frac{15}{2}.

In conclusion, the average rate of change of the function from x=1 to x=2 is \frac{15}{2}.

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9+x

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Among all pairs of numbers whose difference is 20, find a pair whose product is as small as possible. what is the minimum produc
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Answer:

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Step-by-step explanation:

Let the smaller number be x.

Then the larger number is x + 20.

The product is x(x + 20).

Now you can write the function

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y = x^2 + 20x

Take the first derivative of y with respect to x.

y' = 2x + 20

Set the first derivative equal to zero to find the x value for the minimum value of the function.

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The minimum value of the function occurs at x = -10. -10 is one of the two numbers.

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If you have not learned derivatives yet, then plot the function

y = x^2 + 20x

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4 0
3 years ago
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