The circle with center O has two chords AC and EF which are of same length 9.07.
OD and OB are the two perpendiculars drawn from the center O to the two chords AC and EF .It represents the distance of the chords from the centre.
The circle theorem states: congruent chords are equidistant from the center.
OD is congruent to OB.
Option A is the right answer.
The arc angle AC is measured as 55 degrees.
<h3>How to find arc angle?</h3>
If two secant intersect in the exterior of a circle, then the measure of the angle formed is half the positive difference of the arcs intercepted.
Therefore, the secants intersect outside the circle at point E.
The arc angle AC can be found as follows:
Therefore,
m∠BED = 1 / 2 (arc angle AC - arc angle BD)
arc angle AC = x
arc angle BD = 23 degrees.
m∠BED = 16 degrees.
m∠BED = 1 / 2 (arc angle AC - arc angle BD)
16 = 1 / 2 (x - 23)
16 = 1 / 2x - 23 / 2
16 + 11.5 = 0.5x
27.5 = 0.5x
x = 27.5 / 0.5
x = 55 degrees.
Therefore,
arc angle AC = 55 degrees.
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Answer:
B=55
Step-by-step explanation:
2x+3x+2x+5=180
7x=175
X=25
B= 2x+5
B=2*25 +5
B=55
Answer:
C. Translation
Step-by-step explanation:
This is because the triangle is still in the same position, however, it has been shifted to the right five and up two.
Hope this helps!
All the love, Ya boi Fraser :)
Answer:
a=k-w+v
Step-by-step explanation:
k/a= w-v
a( k/a) = a (w-v)
k -w + v =a
