R = red beads
G = green beads
B = blue beads
Given:
R/2 = G/3 = B/7
B = R + 150
How many reds?
R/2 = (R+150)/7
7*R/2 = R + 150
7*R = 2*R + 300
5*R = 300
R = 60
How many blue?
B = R + 150
B = 210
How many green?
G/3 = R/2
G/3 = 60/2
G/3 = 30
G = 90
How many total?
Total = R+G+B
Total = 60+90+210
Total = 360
Answer:
the width is 9 23/30 feet ≈ 9.767 ft
Step-by-step explanation:
Let w represent the width of the train car. Then 6 times the width is 6w, and 8 ft less than that is (6w-8). We are told this amount is 50.6 feet, so we have ...
6w -8 = 50.6
6w = 58.6 . . . . . . . add 8; next divide by 6
58.6/6 = w = 586/60 = 293/30 = 9 23/30 . . . . feet
This is a repeating decimal: 9.766666...
The width of the train car is 9 23/30 ft, about 9.77 ft.
Answer:
The general plan is to find BM and from that CM. You need 2 equations to do that.
Step One
Set up the two equations.
(7 - BM)^2 + CM^2 = (4*sqrt(2) ) ^ 2 = 32
BM^2 + CM^2 = 5^2 = 25
Step Two
Subtract the two equations.
(7 - BM)^2 + CM^2 = 32
BM^2 + CM^2 = 25
(7 - BM)^2 - BM^2 = 7 (3)
Step three
Expand the left side of the new equation labeled (3)
49 - 14BM + BM^2 - BM^2 = 7
Step 4
Simplify And Solve
49 - 14BM = 7 Subtract 49 from both sides.
-49 - 14BM = 7 - 49
- 14BM = - 42 Divide by - 14
BM = -42 / - 14
BM = 3
Step Five
Find CM
CM^2 + BM^2 = 5^2
CM^2 + 3^2 = 5^2 Subtract 3^2 from both sides.
CM^2 = 25 - 9
CM^2 = 16 Take the square root of both sides.
sqrt(CM^2) = sqrt(16)
CM = 4 < Answer
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
substitute x for 6 and y for 1
which will be 6-1+6
using BODMAS
6-(1+6)
6-7= -1
