What is 53 divided by 34

Perform the operation. Write your answer in scientific notation. 7×10^6-5.3×10^6

Lady_Fox [76]

7 • 10^6 - 5.3 • 10^6
= 1.7 • 10^6 in scientific notation

6 0

3 years ago

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I have a roof that measures 175 ft by 45 ft. During the hurricane 11 inches of rain fell.

Nikolay [14]

Answer:

4.1 billion

Step-by-step explanation:

1 ft = 30.48 cm

1 in = 2.54 cm

The volume of rain that fell on the roof is given by ...

V = LWH

V = (175 ft × 30.48 cm/ft)(45 ft × 30.48 cm/ft)(11 in × 2.54 cm/in)

= 175×45×11×30.48²×2.54 cm³ = 204,412,236.336 cm³

At 20 drops per cm³, this will be ...

20×204,412,236.336 ≈ 4,088,244,727 . . . . raindrops

About 4.1 billion raindrops fell on your roof.

5 0

3 years ago

2x+22=4(x + 3). Can you help?

enot [183]

First, you will start with distributive property. on the right side you will distribute 4 into x and 3.

the equation will become:
2x + 22 = 4x + 12

then you have to get x on only one side of the equal sign. subtract 2x from 4x and the equation becomes:
22 = 2x + 12

subtract 12 from 22:
10 = 2x

divide 10 by 2:
5 = x
or
x = 5

(:

5 0

3 years ago

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An acute triangle has two sides measuring 8 cm and 10 cm. What is the best representation of the possible range of values for th

anastassius [24]

Answer:

your second choice

Step-by-step explanation:

4 0

2 years ago

The weight of an organ in adult males has a bell-shaped distribution with a mean of 330 grams and a standard deviation of 15 gr

wolverine [178]

Answer: a) (315,345) b) 99.7%, c) 0.14%, d) 97.36%

Step-by-step explanation:

Since we have given that

Mean = 330 grams

Standard deviation = 15 grams

(a) About 68% of organs will be between what weights? 

We will use 68-95-99.7 rule, it is empirical.

as we know that

$P(\mu-\sigma\leq X\leq \mu +\sigma)\approx 0.6827$

So,

$\mu -\sigma=330-15=315\\\\\mu+\sigma=330+15=345$

So,the 68% of the data falls within three standard deviation or will be between (315 grams and 345 grams)

(b) What percentage of organs weighs between 285 grams and 375 grams?

$\mu+3\sigma=330+3\times 15=330+45=375\\\\\mu-3\sigma=330-3\times 15=330-45=285$

so, 99.7 % of organs weighs between 285 grams and 315 grams, because the these two values are within one standard deviation of the mean.

(c) What percentage of organs weighs less than 285 grams or more than 375 grams? 

Since it is 3 standard deviation below the mean and 3 standard deviations above the mean.

so, it becomes

$1-0.9973=0.0027\\\\\dfrac{0.0027}{2}=0.00135\\\\So,0.00135\times 100=0.135\%=0.14\%$

Since 285 grams is 3 standard deviation below the mean(=330 grams) and 375 grams is 3 standard deviation above the mean(=330 grams).

So 0.14% data is lies below the 285 grams and 0.14% data is lies above the 375 grams.

(d) What percentage of organs weighs between 300 grams and 375 grams?

$\mu-2\sigma=330-2\times 15=330-30=300\\\\\mu+3\sigma=330+3\times 15=330+45=375$

So, 300 grams is 2 standard deviation below the mean i.e. 330 grams and 375 grams is 3 standard deviation above the mean i.e. 330 grams.

so, percentage of organs weighs would be

$100-2.5-0.14=97.36\%$

Hence, a) (315,345) b) 99.7%, c) 0.14%, d) 97.36%.

4 0

3 years ago

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