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sergejj [24]
3 years ago
13

What is 53 divided by 34

Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0
53 divided by 34 is 1.558823529
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Help me out, please!
VMariaS [17]

Answer:

y = 2/3(x - 3)

Step-by-step explanation:

slope of the line is 2/3

we can use point (3,0)

formula: y - y = m(x - x)

y - 0 = 2/3 (x - 3)

y = 2/3(x - 3)

5 0
2 years ago
Please answer these questions asap please!!! Thank you!
Len [333]

Answer:

a= 1%

b= 0.1%

c= 0.1875% probably have to round

Step-by-step explanation:

a= 2/2= 1

B= 1/10=0.1

c= 1.5/8= 0.1875

6 0
3 years ago
A certain big company classifies its employees according to gender, age-group (6 categories) and employment type (10 categories)
elena-14-01-66 [18.8K]

We don’t know the number of employees remaining at the company.

We don’t know the total number of employees remaining at the company.

The classification consists of gender, division, and employment type.

It doesn’t matter what order those attributes come in. A person who is male, age group 6, and employment type 10 has the same classification as someone who is of employment type 6, male, and age group10.

Therefore since order does not matter it is a combination question.

Assuming only two genders are allowed (you didn’t say and some people think there are about 10 of them)

It is either 120 (2 times 6 times 10) or "None of the above" if you believe there are more than 2 genders.

2×6×10=120

Learn more about employees at

brainly.com/question/1190099

#SPJ4

3 0
1 year ago
A teacher has a total of 7/9 bucket of water to pour into pots with flowers that are standing in equal quantities on two windows
AleksAgata [21]

Answer:

14 pots

Step-by-step explanation:

if teacher pours 1/18 in each pot and there was 7/9 buckets in total, 9 fits into 18 twice so just 7X2 =14 and 9X2=18 so 14 pots were watered

hope this helps

3 0
2 years ago
(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x

\cot^2 x = \cot^2 x


8 0
3 years ago
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