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VashaNatasha [74]
2 years ago
15

At a competition with 4 runners, 4 medals are rewarded for first place through fourth place. Each model is different. How many w

ays are there to award the medal?
Decide if the situation involves a permutation or a combination, and then find the number of ways to award the medals.

A. Permutation; number of ways =24
B. Combination; number of ways = 24
C. Permutation; number of ways = 1
D. Combination; number of ways =1
Mathematics
2 answers:
GrogVix [38]2 years ago
7 0

Answer:

Option A. Permutation; number of ways = 24

Step-by-step explanation:

At a competition with 4 runners, 4 medals are rewarded for place place to fourth place.

We have to tell in this situation we will use permutation or combination to find the number of ways, medals can be rewarded.

We know when order matters then permutation is applied.

So number of ways to award the medals will be = 4! = 4×3×2×1 = 24

Therefore, option A. permutation : number of ways = 24 is the answer.

MrRissso [65]2 years ago
6 0

A. Permutation; number of ways =24

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Find the area. Simplify your answer.
Colt1911 [192]

Answer:

x = 26

Step-by-step explanation:

it is a right angle so

(x+4)3=90

3x+12=90

-12         -12

3x = 90-12

3x = 78

/3       /3

x = 26

7 0
3 years ago
Given the similarity statement<br> AJKL ANOP, what's the<br> corresponding side of ON ?
levacccp [35]

Answer:

ON = KJ

Step-by-step explanation:

JKL = NOP

We know the angles match

<J = <N

<K = <O

< L = <P

And we know

JK = NO

KL =  OP

JL = NP

We are looking for ON = KJ

5 0
3 years ago
Read 2 more answers
The time to fly between New York City and Chicago is uniformly distributed with a minimum of 120 minutes and a maximum of 150 mi
lara [203]

Answer:

a) 33.33%)

b) 135 minutes

c) 8.66 min

d) 50%

Step-by-step explanation:

a) the probability for a uniform distribution is

P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values

therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)

P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)

b) the mean (expected value) for a uniform probability distribution is

E(X) = (c+d)/2 = (120+150)/2 = 135 minutes

c)  the standard deviation for a uniform probability distribution is

σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²

σ = √75 min² = 8.66 min

b) following the same procedure as in a)

P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)

4 0
3 years ago
A certain truck weighs 2 metric tons A person weighing 60 kg get in the truck followed by a 70 kg person how many kilograms does
DiKsa [7]
The truck now weighs 2130 kilograms. Hope this helps.
7 0
3 years ago
What is the sum of the first 70 consecutive odd numbers? Explain.
expeople1 [14]

The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.

Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.

So, if we sum the first N odd numbers, we have

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

\displaystyle 2\sum_{i=1}^N i = 2\cdot\dfrac{N(N+1)}{2}=N(N+1)

The second sum is simply the sum of N ones:

\underbrace{1+1+1\ldots+1}_{N\text{ times}}=N

So, the final result is

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1 = N(N+1)-N = N^2+N-N = N^2

which ends the proof.

5 0
2 years ago
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