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Mariana [72]
3 years ago
10

Help me please I need help

Mathematics
1 answer:
Ainat [17]3 years ago
5 0

Answer:

Use the 45-45-90 rule.

Step-by-step explanation:

Based on angle A being 45 and angle B looking like its 90 degrees, angle C will be 45 degrees and so you'd use the 45-45-90 rule, which is a special right triangle. The 45 degrees sides are x and the hypotenuse is x\sqrt{2}. It will be easier if you look it up to see a graphic of it, but I'm pretty sure that both sides CB and AB are 6 based on this rule.

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Answer:

\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }

\boxed { \frac{3}{5}y } \to \: \boxed {y -  \frac{2}{5}y }

Step-by-step explanation:

We need to simplify

y +  \frac{2}{5}y

We collect LCM to get;

\frac{5y + 2y}{5}  =  \frac{7y}{5}

Therefore:

\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }

Also we need to simplify:

y -  \frac{2}{5}y

We collect LCM to get;

y -  \frac{2}{5}y =  \frac{5y - 2y}{5}  =  \frac{3}{5} y

Therefore

\boxed { \frac{3}{5}y } \to \: \boxed {y -  \frac{2}{5}y }

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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