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Liono4ka [1.6K]
3 years ago
13

Your corporation hosts a Web site at the static public IP address 92.110.30.123.

Computers and Technology
1 answer:
ladessa [460]3 years ago
7 0

Answer:

Check the explanation

Explanation:

In line with the question, we can now derive that:

The router's outside interface IP address will be 92.110.30.65.

The router's inside interface IP address will be 192.168.11.254.

The Web site's IP public IP address will be 92.110.30.123.

The private IP address of the backup Web server will be 192.168.11.110.

and when we say IP address, it stands for Internet Protocol, it is a set of usual predefined rules which are utilized to administrate the manner to which data packets are sent over the internet. An IP address, which is typically just identified as an IP, is a sequence of figures used to uniquely recognize a computer/device on a particular network or on the internet space.

You might be interested in
Write a class called DisArray with methods to convert a 1-dimensional array to a 2-dimensional array. The methods' name should b
meriva
<h2>Answer:</h2>

=======================================================

//Class header definition

public class DisArray {

   //First method with int array as parameter

   public static void convert2D(int[] oneD) {

       //1. First calculate the number of columns

       //a. get the length of the one dimensional array

       int arraylength = oneD.length;

       //b. find the square root of the length and typecast it into a float

       float squareroot = (float) Math.sqrt(arraylength);

       //c. round off the result and save in a variable called row

       int row = Math.round(squareroot);

       //2. Secondly, calculate the number of columns

       //a. if the square of the number of rows is greater than or equal to the

       //length of  the one dimensional array,

       //then to minimize padding, the number of

       //columns  is the same as the number of rows.

       //b. otherwise, the number of columns in one more than the

       // number of rows

       int col = ((row * row) >= arraylength) ? row : row + 1;

       //3. Create a 2D int array with the number of rows and cols

       int [ ][ ] twoD = new int [row][col];

       //4. Place the elements in the one dimensional array into

       //the two dimensional array.

       //a. First create a variable counter to control the cycle through the one

       // dimensional array.

       int counter = 0;

       //b. Create two for loops to loop through the rows and columns of the

       // two  dimensional array.

       for (int i = 0; i < row; i++) {

           for (int j = 0; j < col; j++) {

               //if counter is less then the length of the one dimensional array,

               //then  copy the element at that position into the two dimensional

               //array.  And also increment counter by one.

               if (counter < oneD.length) {

                   twoD[i][j] = oneD[counter];

                   counter++;

              }

              //Otherwise, just pad the array with zeros

               else {

                   twoD[i][j] = 0;

               }

           }

       }

       //You might want to create another pair of loop to print the elements

       //in the  populated two dimensional array as follows

       for (int i = 0; i < twoD.length; i++) {

           for (int j = 0; j < twoD[i].length; j++) {

               System.out.print(twoD[i][j] + " ");

           }

           System.out.println("");

       }

   }     //End of first method

   //Second method with String array as parameter

   public static void convert2D(String[] oneD) {

       //1. First calculate the number of columns

       //a. get the length of the one dimensional array

       int arraylength = oneD.length;

       //b. find the square root of the length and typecast it into a float

       float squareroot = (float) Math.sqrt(arraylength);

       //c. round off the result and save in a variable called row

       int row = Math.round(squareroot);

       //2. Secondly, calculate the number of columns

       //a. if the square of the number of rows is greater than or equal to the length of  

       //the one dimensional array, then to minimize padding, the number of

       //columns  is the same as the number of rows.

       //b. otherwise, the number of columns in one more than the

       //number of rows.

       int col = (row * row >= arraylength) ? row : row + 1;

       //3. Create a 2D String array with the number of rows and cols

       String[][] twoD = new String[row][col];

       //4. Place the elements in the one dimensional array into the two

       // dimensional array.

       //a. First create a variable counter to control the cycle through the one

       // dimensional array.

       int counter = 0;

       //b. Create two for loops to loop through the rows and columns of the

       //two  dimensional array.

       for (int i = 0; i < row; i++) {

           for (int j = 0; j < col; j++) {

               //if counter is less then the length of the one dimensional array,

               //then  copy the element at that position into the two dimensional

               //array.  And also increment counter by one.

               if (counter < oneD.length) {

                   twoD[i][j] = oneD[counter];

                   counter++;

               }

               //Otherwise, just pad the array with null values

               else {

                   twoD[i][j] = null;

               }

           }

       }

       //You might want to create another pair of loop to print the elements  

       //in the populated two dimensional array as follows:

       for (int i = 0; i < twoD.length; i++) {

           for (int j = 0; j < twoD[i].length; j++) {

               System.out.print(twoD[i][j] + " ");

           }

           System.out.println("");

       }

   }    // End of the second method

   //Create the main method

   public static void main(String[] args) {

       //1. Create an arbitrary one dimensional int array

       int[] x = {23, 3, 4, 3, 2, 4, 3, 3, 5, 6, 5, 3, 5, 5, 6, 3};

       //2. Create an arbitrary two dimensional String array

       String[] names = {"abc", "john", "dow", "doe", "xyz"};

       

       //Call the respective methods

       convert2D(x);

       System.out.println("");

       convert2D(names);

   }         // End of the main method

}            // End of class definition

=========================================================

==========================================================

<h2>Sample Output</h2>

23 3 4 3  

2 4 3 3  

5 6 5 3  

5 5 6 3  

abc john dow  

doe xyz null

==========================================================

<h2>Explanation:</h2>

The above code has been written in Java and it contains comments explaining each line of the code. Please go through the comments. The actual executable lines of code are written in bold-face to distinguish them from the comments.

8 0
3 years ago
What does D'Artagnan discover about Milady? d. That she has the mark of a criminal, the fleur- c. That she is secretly working f
Setler79 [48]
The answers is b .....
6 0
3 years ago
Read 2 more answers
The instant pivot button is displayed in the statistics and visualization tabs when a _______ search is run.
Arisa [49]

Answer:

<h2>The instant pivot button is displayed in the statistics and visualization tabs when a <u>non-transforming</u>  search is run. </h2>

Explanation:

<h3>Transforming Search:</h3>

It can be defined as a search in which transforming commands are used that involve, charts and stats to convert data of events that is gained by the search in to tables (statistical). These tables can further be used for the basis of visualizing data in the form of charts.

Non-Transforming Search:

The search that do no contains produce event lists that can be viewed in Events tab. while using non-transforming search, i we want to generate tables or charts we must follow the points below:

  • Click ob statistics and Visualization tab.
  • Select pivot to open the search.
  • All the visualizations can be generated in this editor.

<h2>i hope it will help you!</h2>
5 0
4 years ago
Write a for loop to print all NUM_VALS elements of array hourlyTemp. Separate elements with a comma and space. Ex: If hourlyTemp
MA_775_DIABLO [31]

Answer:

  1. #include <iostream>
  2. using namespace std;
  3. int main()
  4. {
  5.    const int NUM_VALS = 4;
  6.    int hourlyTemp[NUM_VALS];
  7.    int i;
  8.    
  9.    for (i = 0; i < NUM_VALS; ++i)
  10.    {
  11.        cin >> hourlyTemp[i];
  12.        
  13.    }
  14.    
  15.    /* Your solution goes here */
  16.    for(i = 0; i < NUM_VALS; ++i){
  17.        
  18.        if(i < NUM_VALS -1){
  19.            cout<<hourlyTemp[i]<<",";
  20.        }
  21.        else{
  22.            cout<<hourlyTemp[i];
  23.        }
  24.    }
  25.    cout << endl;
  26.    return 0;
  27. }

Explanation:

The solution code is given from Line 18 - 26. To print the element from array one after another, we create a for loop to traverse through every element in the array (Line 18). Create an if condition to check if the current index i is not the last index, print the element followed with a comma (Line 20 -22). Otherwise print only the element (Line 23 - 25).

8 0
3 years ago
2. Imagine you play a game of fetch with the dog. It takes the dog 60 seconds to run a total of 180 meters. What was the dog's a
vodka [1.7K]

180 meters in 60 seconds is an average speed of 180m/60s = 3 m/s.

3 0
4 years ago
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