Disk access is way slower than
memory access. Caching is a technique to improve the disk access time. Block cache is a caching technique which
reduces disk accesses time. Here a
portion of disk is bought to cache for reading and a modified blocks are first
changed in cache but reflected in the disk at one go. On the other hand with write through caching
each modified block is written to cache and at the same time it is written to
the disk. Write- through caching
requires more disk I/O so they can have a negative effect on the performance.
I need some more information. If you need any more help with this please leave a relpy.
Answer:
Algorithm:
1. Declare an integer variable N.
2. Read the value N from user.
3.While(N):
3.1 find r=N%10;
3.2 print r in new line.
3.3 Update N as N=N/10.
4.end program.
Implementation in C++.
// header
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variable
int N;
cout<<"Enter an Integer:";
cin>>N;
// find the digits of number
while(N)
{
// last digit
int r=N%10;
// print last digit
cout<<r<<endl;
// update the number
N=N/10;
}
return 0;
}
Output:
Enter an Integer:329
9
2
3
Answer: True
Explanation:
Yes, the given statement is true that a DFA is equivalent to NFA in terms of power. For any type of NFA we can easily build an equal DFA so, the NFA are not much powerful as compared to DFA. Both NFA and DFA are characterized by a similar type of class.
DFA is a special case of NFA and They both defined in the same class of language. Each condition in the DFA get summarized by all the condition that the NFA has itself.
Answer:
Explanation:
a) taking 00000005, it is a 13th bit which is 0, and therefore, we'd call it an ordered chunk
b) taking 00000005 again, it is 14th (B) and 15th (E) bits are 0 and so we'd call it a middle fragment
c) 00000015 is equal to 21, it is not a multiple of 4, and as such, it needs 3 padding bytes
d) 00000005 is equal to 5 making it a TSN. So the TSN is 5
e) taking 0003, we can then say the SI is 3
f) taking 000A, the SSN is then 10
g) the message is 48656C6C
