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KIM [24]
3 years ago
15

How to write 8 21/40 as a decimal

Mathematics
1 answer:
timofeeve [1]3 years ago
6 0
8 \frac{21}{40}   ~~ =\ \textgreater \ ~~   \frac{8*40+21}{40}    ~~ =\ \textgreater \ ~~   \frac{341}{40}    ~~ =\ \textgreater \ ~~  8.525
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PLEASE HELP!!!!! I DONT UNDERSTAND!!!! :(
Misha Larkins [42]
There are 365 days in a year, well,unless is a leap-year, but we're assuming 365 days per year, now, "t" is how many years it takes for population to grow to "P" much, however, 1 day in year terms is really just 1/365 year or about 0.003 years, and 2 days is just 2/365 year, and  3 days is 3/365 year and so on, thus,

\bf \stackrel{\textit{in years}}{P=25,000(1.0095)^t}\qquad \qquad \qquad \stackrel{\textit{in days}}{P=25,000(1.0095)^{\frac{t}{365}}}
7 0
3 years ago
A telescope contains both a parabolic mirror and a hyperbolic mirror. They share focus ​, which is 46feet above the vertex of th
uranmaximum [27]

the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.

The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.

In terms of hyperbola, F1F2=2c, c=20.

The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.

Use formula c^2=a^2+b^2c

2

=a

2

+b

2

to find b:

\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}

(20)

2

=(18)

2

+b

2

,

b

2

=400−324=76

.

The branches of hyperbola go in y-direction, so the equation of hyperbola is

\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1

b

2

y

2

−

a

2

x

2

=1 .

Substitute a and b:

\dfrac{y^2}{76}- \dfrac{x^2}{324}=1

76

y

2

−

324

x

2

=1 .

7 0
3 years ago
If Sarah subtracts five times her number from 24, she gets 4. Wha Sara's number?
zheka24 [161]

Answer:

4

Step-by-step explanation:

24 - (5 x 4)

= 24 - 20

= 4

Sarah's number is 4.

6 0
3 years ago
Read 2 more answers
Find the 53rd term of the arithmetic sequence<br> 27,11, -5
vivado [14]

Answer:

The 53rd term of this arithmetic sequence is -805.

Step-by-step explanation:

The general rule of an arithmetic sequence is the following:

a_{n+1} = a_{n} + d

In which d is the common diference between each term, that is, d = a_{3} - a_{2} = a_{2} - a_{1}.

To find the nth term of the sequence, this equation can be written as:

a_{n} = a_{1} + (n-1)d

27,11, -5

So a_{1} = 27, a_{2} - a_{1} = 11 - 27 = -16[/tex[tex]a_{n} = a_{1} + (n-1)d

a_{53} = a_{1} + (52)d = 27 + 52*(-16) = -805

The 53rd term of this arithmetic sequence is -805.

3 0
3 years ago
if there is a 10% chance of sun tomorrow and 20% chance of wind and no sun what is the probability that it is windy given that i
harkovskaia [24]

Answer:

=22%

Step-by-step explanation:

Since we have given two conditions simultaneously that is windy and not sunny. So we will use the concept of conditional probability.

The probability of sunny day= P(sunny)=10%

P(sunny)=10%=0.1

The probability of windy and not sunny=P(windy|not sun)=20%

P(windy|not sun)=20% = 0.2

Now divide the both probabilities:

P(windy|not sun)/P(sunny)

=0.2/[1-0.1]              

{Hence there are 10% chances of sun tomorrow than there are (1 - 0.1) chances of no sun}

If we subtract 1 from 0.1 than it becomes:

=0.2/0.9

=2/9

=0.2222222222

=22%

Hence the probability that it is windy = 22% ....

6 0
3 years ago
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