Answer:
Expected Value of M is 50 and the Standard Error of M is 3
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation, also called standard error
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
µ = 50 and σ = 18
For the sample
Mean 50 and standard error
.
The answer is:
Expected Value of M is 50 and the Standard Error of M is 3
Answer:
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Step-by-step explanation:
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We can use law of cosines to find the length of the third side.
Law of cosines is:
c^2 = a^2 + b^2 - 2ab*cos(C), where angle C is opposite of side c.
Plug in what we know.
c^2 = 3^2 + 4^2 - 2(3)(4)cos(60)
Simplify:
c^2 = 9 + 16 - 24cos(60)
c^2 = 25 - 24cos(60)
Solve for c by taking the square root of both sides:
c = sqrt(25 - 24cos(60))
c = sqrt(25 - 24(0.5))
c = sqrt(13)
c = 3.606
Answer:
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Answer:
m∠CBD = m∠CDB ⇒ proved
Step-by-step explanation:
Let us solve the question
∵ AB ⊥ BD ⇒ given
→ That means m∠ABD = 90°
∴ m∠ABD = 90° ⇒ proved
∵ ED ⊥ BD ⇒ given
→ That means m∠EDB = 90°
∴ m∠EDB = 90° ⇒ proved
∵ ∠ABD and ∠EDB have the same measure 90°
∴ m∠ABD = m∠EDB ⇒ proved
∵ m∠ABD = m∠ABC + m∠CBD
∵ m∠EDB = m∠EDC + m∠CDB
→ Equate the two right sides
∴ m∠ABC + m∠CBD = m∠EDC + m∠CDB
∵ m∠ABC = m∠EDC ⇒ given
→ That means 1 angle on the left side = 1 angle on the right side, then
the other two angles must be equal in measures
∴ m∠CBD = m∠CDB ⇒ proved