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Airida [17]
2 years ago
15

Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero.

Mathematics
1 answer:
timama [110]2 years ago
5 0

Answer:

hahahhaa thanks

Step-by-step explanation:

ahahahhahahad

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elena-14-01-66 [18.8K]

Answer:

Sangayko venchitra ko asalokan gari nimna samuhko ganatmak sankhya Pata lagaunuhos

N(A)

3 0
2 years ago
Photo attached please help
aniked [119]
C and E that is the answer
4 0
3 years ago
In a carnival game, there is a 45% probability of winning a prize. Which of the following is true.
JulsSmile [24]
Ok, here is what I got:
<span>9/20 is .45 so D is right for sure. C is also correct since the remaining % is 55 ( meaning the percent you won't win) this is also the same as A which is 11/20 or .55. again meaning that .55 is the probability that you won't win. I hope this helps!</span>
7 0
3 years ago
Read 2 more answers
1) A sprint runner can run 10 laps around a track in
Arada [10]

Answer:

so, 10 laps in 25 mins we want to make mins=1 so

10/25=2/5 times 5/5=2/5

if you multiply 2/5 by 2/2 then you get 4/10 and 4/10=0.4

the runner can run 0.4 or 2/5 lap in 1 minute

Step-by-step explanation:

it is the answer box I'm a genius

6 0
2 years ago
Please help me out with this!!<br> BRAINLIEST AVAILABLE!!
lapo4ka [179]

Answer:

xy = 1

k = 79

Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2                        Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3)         Remove the brackets

2y + 6 = 2x + 6           Subtract 6 from both sides

2y = 2x                       Divide by 2

y = x

Now solve these two equations.

so x^2 = x                  

x > 0

1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x                           Divide both sides by x            

x = 1                            

y = x^2                           Put x = 1 into x^2

y = 1^2                           Solve

y = 1                      

The second solution is

(1,1)

xy = 1*1

xy = 1

Answer: A

Question Two

square root(k + 2) - x = 0

Subtract x from both sides

sqrt(k + 2) = x                Square both sides

k + 2 = x^2                    Let x = 9

k + 2 = 9^2                    Square 9

k + 2 = 81

k = 81 - 2

k = 79

4 0
3 years ago
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