Follow PEMDAS.
Parenthesis
Exponents
Multiplication & Division
Addition & Subtraction
Alright, do multiplication first, then division. Then, do subtraction then addition.

Hope this helped!
Cost of 6 sweets = 24p
so, cost of 1 sweet = 24p/6 = 4p
Now, cost of 5 sweets will be =4p*5 = 20p
Answer:

Step-by-step explanation:
<u>Perfect squares</u>: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...
To find
, identify the perfect squares immediately <u>before</u> and <u>after</u> 75:


See the attachment for the correct placement of
on the number line.
Y = 5 - 4x
5 - 4x = x^2 - 2x - 19
0 = x^2 + 2x -24
0 = (x + 6)(x - 4)
Therefore x = -6 (Given) or 4
x = 4, y = -9
(4,-9) is the other solution
Answer:
c
Step-by-step explanation:
4 times 5 is 20 and 20 times 6 is 120