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natali 33 [55]
3 years ago
8

1. Use the graph to make a linear model of each function. Write a system of equations and state what the solution represents.

Mathematics
1 answer:
Vesnalui [34]3 years ago
7 0

Answer:

ok so 300 square feet so draw a line there

Step-by-step explanation:

sorry if im not crocect

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F(x) = -3x – 2<br> g(x) = 2x + 5<br> Find (f*g)(5)
antiseptic1488 [7]

Answer:

hope it will help u in understanding

3 0
3 years ago
If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t
Sergio039 [100]

From the given information we can write the equation:

-16t^2 +96t + 4 = 112

-16t^2 + 96t + 4 - 112 = 0

-16t^2 + 96t - 108 = 0

simplify, change the signs, divide by -4

4t^2 - 24t + 27 = 0


You can use the qudratic formula but this will factor to

(2t-3)(2t-9) = 0

Two solutions

t = 3/2

t = 1.5 seconds at 112 ft on the way up

and

t = 9/2

t = 4.5 seconds at 112 ft on the way back down

Graphically, (green line is 112 ft)


5 0
3 years ago
help me please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Sunny_sXe [5.5K]
So thi sis really simple since you have an equal sign so



(n/3)-(5n/6)=1/3
to subtract fractions, make the bottom number the same
n/3 times 2/2=2n/6
(2n/6)-(5n/6) or (2n-5n)/6 so
-3n/6=1/3
multiply both sides by 6
-3n=6/3=2
-3n=2
divide both sides by 3
-n=2/3
mmultiply boht by -1
n=-2/3
tada
n=-2/3
6 0
3 years ago
Read 2 more answers
Please answer I will give brainliest
Eddi Din [679]
Felipe earned 375 dollars each week because if you divide 4,500 to 12.
3 0
3 years ago
Suppose each edge of the cube shown in the figure is 10 inches long. Find the sine and cosine of the angle formed by diagonals D
tatiyna

Check the picture below.

sin(EDG )=\cfrac{\stackrel{opposite}{10}}{\underset{hypotenuse}{10\sqrt{3}}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{sin(EDG )=\cfrac{\sqrt{3}}{\sqrt{3^2}}\implies sin(EDG )=\cfrac{\sqrt{3}}{3}} \\\\[-0.35em] ~\dotfill

cos(EDG )=\cfrac{\stackrel{adjacent}{10\sqrt{2}}}{\underset{hypotenuse}{10\sqrt{3}}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{cos(EDG )=\cfrac{\sqrt{6}}{\sqrt{3^2}}\implies cos(EDG )=\cfrac{\sqrt{6}}{3}}

4 0
2 years ago
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