Answer:
184
Step-by-step explanation:
Answer:
2 real solutions
Step-by-step explanation:
We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:
b² - 4ac
If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.
Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:
b² - 4ac
(-20)² - 4 * 6 * 1 = 400 - 24 = 376
Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.
<em>~ an aesthetics lover</em>
Answer:
3k+3
Step-by-step explanation:
Answer:
- 12k² + kl
Step-by-step explanation:
Given
7kl - 3k(4k + 2l) ← distribute parenthesis by - 3
= 7kl - 12k² - 6kl ← collect like terms
= - 12k² + kl