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2 years ago

Which angle pairs are supplementary? Check all that apply.

Mathematics

2 answers:

Zina [86]2 years ago

7 0

Answer:

Supplementary Angles are two angles the sum of whose measures is 180º. Supplementary angles can be placed so they form a linear pair (straight line), or they may be two separate angles.

ANTONII [103]2 years ago

5 0

Answer:

b) ∠4 and ∠3

c) ∠4 and ∠5

e) ∠3 and ∠6

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Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

3 years ago

Use trigonometric substitution to verify that

photoshop1234 [79]

T = 0
=> Q = 0
t = x
=> Q = arcsin(x/a)
rest it just simple integration of trigonometric function

8 0

3 years ago

Please help me.. I really need it, and I will give you brainlyest:)))

Digiron [165]

Answer:

sdasf sdf

Step-by-step explanation:

so how you ahsbdgkjsgdejgwqjda is how you ajsdbguyaweguidasdh to the question

5 0

3 years ago

Read 2 more answers

A rectangle's length is twice its width. if the perimeter is 66 cm find the width of the rectangle

Lesechka [4]

Perimeter = 2L + 2W

Let x = width and let 2x = length

Perimeter = 66

2x + 2(2x) = 66

2x + 4x = 66 --> 6x = 66 --> x = 66/6 --> x = 11

The width of the rectangle is 11 cm.

6 0

3 years ago

27 Solve for x to the nearest tenth: x² + x - 5 = 0.

Anestetic [448]

Answer:

Step-by-step explanation:

We can use the quadratic formula to get the answer to this

Quadratic Formula: -b +- √b² - 4ac/2a

Once we input A, B, and C into this, and solve any multiplication, we get

x = -1 +- √1 + 20/2

We divide by 2a, which 2a = 2.

-0.5 +- 10.5.

these are the following values of x:

x = 10

x = 11

Pretty sure this is it, hope it helps!

4 0

2 years ago