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ollegr [7]
3 years ago
9

What is 2+2-5×6? ill mark brainliest​

Mathematics
2 answers:
andrey2020 [161]3 years ago
7 0

Answer:

-26

Step-by-step explanation:

2+2−(5)(6)=

-26

swat323 years ago
5 0

Answer:

-26

Step-by-step explanation:

2+2-5×6 = 2+2- -2630 = 4-30 = -26

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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
2 years ago
Patrick earns $20 dollars for every lawn ge mows. write an equation used to find t the total amount of money he hearts from mowi
Kisachek [45]

Answer:

t=20n

Step-by-step explanation:

The answer would be t=20n or something similar because 20n stands for $20 per lawn, which equals t, the total.

3 0
3 years ago
In her wallet, Ms. Thompson has one-dollar, five-dollar and ten-dollar bills totaling $171. She has the same number of five-doll
Phantasy [73]
 6 one-dollars = $6 15 five-dollars = $75 9 ten-dollars = $90 Add them all up to get $171, so that is correct. Add the number of one-dollar bills and the number of ten-dollar bills together. 6 + 9 = 15, which is the number of five-dollar bills, so that is correct as well. Add all the numbers of bills together, 6 + 9 + 15 = 15 + 15 = 30.
4 0
2 years ago
Solve 12x<br>x + 16 - 1 = 0<br>​
zhuklara [117]

Answer:

xx=-0.8

Step-by-step explanation:

not sure if this is right because the 12xx is kind of strange

12xx+16-1=0
12xx+15=0
12xx=-15
12/12xx=12/-15
xx=-.8

5 0
2 years ago
A student spends 40 minutes a day studying how many days per year does the student study?
melomori [17]
All you would have to do is do 40x365 then divide that by 24 hours and that’s you answer!
3 0
3 years ago
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