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Harlamova29_29 [7]
3 years ago
8

What's the answer to x+135=50

Mathematics
1 answer:
Nady [450]3 years ago
4 0

Answer:

x=-85

Step-by-step explanation:

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The total resistance R of two resistors connected in parallel circuit is given by 1/R = 1/R_1 + 1/R_2. Approximate the change in
Naily [24]

Answer:

a) Approximate the change in R is 0.5 ohm.

b) The actual change in R is 0.04 ohm.

Step-by-step explanation:

Given : The total resistance R of two resistors connected in parallel circuit is given by \frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}

To find :

a) Approximate the change in R ?

b) Compute the actual change.

Solution :

a) Approximate the change in R

R_1=12\ ohm and R_2=10\ ohm

R_1 is decreased from 12 ohms to 11 ohms.

i.e. \triangle R_1=21-11=1\ ohm

R_2 is increased from 10 ohms to 11 ohms.

i.e. \triangle R_2=11-10=1\ ohm

The change in R is given by,

\frac{1}{\triangle R}=\frac{1}{\triangle R_1}+\frac{1}{\triangle R_2}

\frac{1}{\triangle R}=\frac{\triangle R_2+\triangle R_1}{(\triangle R_1)(\triangle R_2)}

\triangle R=\frac{(\triangle R_1)(\triangle R_2)}{\triangle R_2+\triangle R_1}

\triangle R=\frac{(1)(1)}{1+1}

\triangle R=\frac{1}{2}

\triangle R=0.5\ ohm

b) The actual change in Resistance

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}

\frac{1}{R}=\frac{1}{12}+\frac{1}{10}

R=\frac{10\times 12}{10+12}

R=\frac{120}{22}

R=5.46\ ohm

When resistances are charged, R_1=R_2=11

\frac{1}{R'}=\frac{1}{R_1}+\frac{1}{R_2}

\frac{1}{R'}=\frac{1}{11}+\frac{1}{11}

R'=\frac{11}{2}

R'=5.5\ ohm

Change in resistance is given by,

C=R'-R

C=5.5-5.46

C=0.04\ ohm

3 0
2 years ago
What two numbers can be multiplied to be -150 and added to be 5
pav-90 [236]
Xy = -150
x + y = 5

     x + y = 5
x - x + y = -x + 5
           y = -x + 5

                                                       xy = -150
                                             x(-x + 5) = -150
                                         x(-x) + x(5) = -150
                                               -x² + 5x = -150
                                     -x² + 5x + 150 = 0
                       -1(x²) - 1(-5x) - 1(-150) = 0
                                  -1(x² - 5x - 150) = 0
                                               -1            -1
                                        x² - 5x - 150 = 0
                                        x = -(-5) ± √((-5)² - 4(1)(-150))
                                                                2(1)
                                        x = 5 ± √(25 + 600)
                                                         2
                                        x = 5 ± √(625)
                                                     2
                                        x = 5 ± 25
                                                 2
                                        x = 2.5 ± 12.5
                                        x = 2.5 + 12.5    or    x = 2.5 - 12.5
                                        x = 15          or          x = -10

    x + y = 5
  15 + y = 5
- 15      - 15
          y = -10
    (x, y) = (15, -10)

            or

    x + y = 5
 -10 + y = 5
+ 10    + 10
           y = 15
    (x, y) = (-10, 15)

The two numbers that add up to 5 and multiply to -150 are 15 and -10.
8 0
3 years ago
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Answer:

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