Solve and check: 5/3z = 15

1. ABCD is a trapezoid with midsegment EF. If AB = 12 and CD = 24, what is the length of EF?

natali 33 [55]

For all of these answers, the equation used was (AB + CD)/2 = EF

1.12+24=36 36/2=18
2. 21 + 35 = 56 56/2 = 28
3. (7 + EF)/2 = 9
multiply by 2
7 + EF = 18
subtract 7
EF = 11

4. (AB + 32)/2 = 22
Multiply by 2
AB + 32 = 44
Subract 32
AB = 12

5. Average

3 0

4 years ago

Read 2 more answers

Pls tell me what the correct answer would be ❤️

mrs_skeptik [129]

Answer:

Step-by-step explanation:

The error is in the second step. For some unknown reason, the x was dropped and the 3 was subtracted from the 7.

It should be

9x +3x + 12 = 7

12x + 12 = 7 Subtract 12 from both sides.

12x + 12 - 12 = 7 - 12 Combine

12x = -5 Divide by 12

12x/12 = -5/12

x = -5/12 or x = - 0.4167

4 0

3 years ago

Two hoses are filling a pool the first hose fills at a rate of x gallons per minute the second hose fills at a rate of 15 gallon

Zielflug [23.3K]

Answer:

B. (0, 5]∪(15,30] only (15,30] contains viable rates for the hoses.

Step-by-step explanation:

The question is incomplete. Find the complete question in the comment section.

For us to meet the pool maintenance company's schedule, the pool needs to fill at a combined

rate of at least 10 gallons per minute. If the inequality represents the combined rates of the hoses is 1/x+1/x-15≥10 we are to find all solutions to the inequality and identifies which interval(s) contain viable filling rates for the hoses. On simplifying the equation;

$\frac{1}{x} + \frac{1}{x-15} \geq \frac{1}{10}\\\\ find\ the \ LCM \ of \ the function \ on \ the \ LHS\\\\\frac{x-15+x}{x(x-15)} \geq \frac{1}{10}\\\\\frac{2x-15}{x(x-15)} \geq \frac{1}{10}\\\\10(2x-15)\geq x(x-15)\\\\20x-150\geq x^2-15x\\\\collect \ like \ terms\\-x^2+20x+15x - 150\geq 0\\$

$-x^2+35x-150 \geq 0\\\\multipply \ through \ by \ minus\\x^2-35x+150 \leq 0\\\\(x^2-5x)-(30x+150) \leq 0\\\\x(x-5)-30(x-5) \leq 0\\\\$

$(x-5)(x-30) \leq 0\\\\x-5 \leq 0 and x - 30 \leq 0\\\\x \leq 5 \ and \ x \leq 30$

The interval contains all viable rate are values of x that are less than 30. The range of interval is (0, 5]∪(15,30]. Since the pool needs to fill at a combined rate of at least 10 gallons per minute for the pool to meet the company's schedule, this means that the range of value of gallon must be more than 10, hence (15, 30] is the interval that contains the viable rates for the hoses.

6 0

3 years ago

Show identity pls Helpp asapp

DIA [1.3K]

Answer:

l.h.s.

seco√(1-sin²o). (here cos²o=1-sin²o)

sec0√cos²o

seco×coso

1/coso×coso

1

r.h.s.

4 0

3 years ago

Lan scores 44 out of 60 marks in a math's test.

Neko [114]

Answer:

73.3%

Step-by-step explanation:

5 0

3 years ago