A(-7,-4) B(-2,0)
√[(x'-x)^2+(y'-y)^2]
√(-2-(-7)^2+(0-(-4)^2
√(5^2)+(4^2)
√25+16
√41
the distance is approximately 6.4 units
-5x + 3x > 22
-2x > 22
x < 22/-2 (greater than sign changes to less than sign when you divide with negative number)
x < -11
Answer:
x=-13 The solution is in the picture above. if you need more solutions let me know. :)
Answer: 20
Reason: They're opposite meaning they are the same when compared to the side
Answer:
b=4a
Step-by-step explanation: