You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)
Answer:
Step-by-step explanation:
5x + 9y = -11
3x + 9y = -3
5x + 9y = -11
-3x - 9y = 3
2x = -8
x = -4
-12 + 9y = -3
9y = 9
y = 1
(-4, 1)
Answer is C
Answer:
Step 1: Find the quotient.
Step 2: Subtract the result from 1.
Step 3: Multiply the result by –2.
Step 4: Add the result to 4 + x2.
Step-by-step explanation:
Edge
Answer:
y = -3x + 6
Step-by-step explanation:
Slope-intercept form:
y = mx + b
m (slope) =
or -3
b (y-intercept, or where the line crosses the y-axis) = 6
y = -3x + 6