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oksian1 [2.3K]
3 years ago
12

The graph models the function y = −x2 − x + 6. Which attribute(s) of the graph tell you the root(s) of the function? Determine t

he root(s).
Mathematics
2 answers:
Alex73 [517]3 years ago
7 0
In a graph the roots of the function are given by the cut points with the x axis.
 On the other hand, we have the following equation:
 y = -x2 - x + 6
 To find the roots, we equate to zero:
 -x2 - x + 6 = 0
 Rewriting we have:
 x2 + x - 6 = 0
 (x-2) (x + 3) = 0
 The roots are:
 x1 = 2
 x2 = -3
 Answer:
 
The roots are:
 
x1 = 2
 
x2 = -3
vlada-n [284]3 years ago
5 0

Answer:

Roots are -3, 2

Step-by-step explanation:

y = −x^2 − x + 6

To find out the roots we set y=0 and solve for x

0 = -x^2 -x+6

Factor out -1

0=-1(x^2+x-6)

divide both sides by -1

x^2 +x -6=0, factor x^2 +x-6

product is -6 and sum +1

3* (-2) = -6

3-2= 1

so factors are 3 and -2

x^2 +x -6=0

(x+3)(x-2)=0

Set each factor =0 and solve for x

x+3 =0 , so x=-3

x-2=0, so x= 2

Roots are -3, 2

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A jet travels from chicago to kansas city at a speed of 440 knots. If it takes a plane 3 hr longer to fly from kansas city to ch
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d = distance between the two cities

v₁ = average speed while going from chicago to kansas city = 440 knots

t₁ = time taken to travel distance going from chicago to kansas city

time taken to travel distance going from chicago to kansas city is given as

t₁ = d/v₁

t₁ = d/440                                        eq-1


v₂ = average speed while going from kansas city to chicago = 110 knots

t₂ = time taken to travel distance going from kansas city to chicago

time taken to travel distance going from kansas city to chicago is given as

t₂ = d/v₂

t₂ = d/110                                                     eq-2


Given that :

t₂ = t₁ + 3

using eq-1  and eq-2

(d/110) = (d/440) + 3

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7 0
4 years ago
A racing car used 255 litres of fuel to complete a 340 km race.
Kisachek [45]
The answer is 151 km.
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3 years ago
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When will I have to use factoring in real life
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ANSWER:

dividing something into equal pieces, exchanging money, comparing prices, understanding time and making calculations during travel.

6 0
3 years ago
3. Solve:
Leto [7]

Answer: A

Step-by-step explanation:

Take 2 equations that make one of their letters disappear, and add them up:

2x + y + z = 1

 x - y + 4z = 0

------------------------

3x + 5z = 1

Do the same with another 2 equations in which the letter, in this case y, can be removed. If you can't, take 2 of 3 equations and equal the value of the letter to make it eliminable.

x - y + 4z = 0

x + 2y - 2z = 3

Since we can't eliminate y, we have multiply as necessary to make it eliminable:

2 (x - y + 4z = 0)

= 2x - 2y + 8z = 0

add all up:

2x - 2y + 8z = 0

 x + 2y - 2z = 3

-----------------------------

3x + 6z = 3

Now we've gone from a 3-variable equation to a 2-variable equation.

3x + 5z = 1

3x + 6z = 3

We can solve again by elimination; to get rid of z, for example, we cross multiply. the upper equation by 6 and the lower equation by 5. However, we have to make one of them negative in order to make them eliminable.

6 (3x + 5z = 1)

-5 (3x + 6z = 3)

----------------------------

18x + 30z = 6

-15x - 30z = -15

---------------------------

3x = - 9

Solving for x;

x = \frac {-9}{3}

x = - 3

After finding one variable, we can use our 2-variable equations to find the next variable:

3x + 5z = 1

3 (-3) + 5z = 1

- 9 + 5z = 1

5z = 1 + 9

5z = 10

z = \frac{10}{5}

z = 2

Having found these 2 variables, we can put them into one of our main 3-variable equations to find the last one:

2x + y + z = 1

2(-3) + y + 2 = 1

- 6 + y + 2 = 1

y - 4 = 1

y = 1 + 4

y = 5

And you've found all the variables in the equation; to prove if they're correct or not, you can replace them in any of the main equations and the result should be equal to each other:

x + 2y - 2z = 3

-3 + 2(5) - 2(2) = 3

- 3 + 10 - 4 = 3

10 - 7 = 3

3 = 3

7 0
3 years ago
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