The numbers that would be smaller would be the two with the difference of 26.
27-1=26 where as, if you were to use a 1 in each, 99+1= 100. Therefore 27 and 1 (28) is less than 99 and 1 (100).
Answer:
no
Step-by-step explanation:
6-6=0
1-6=-5
9 - 6 + 4 - 8/3 ..,
geometric series a(n) = a1r^(n-1)
r = a(n+1)/a(n)
-6/9 = -2/3
4/-6 = -2/3
-8/3/4 = -2/3
so r = -2/3 and a1 = 9
Sn = a1(1-r^n)/(1-r) = 9(1-(-2/3)^n)/(1-(-2/3))
n is infinite Sn = 9/(5/3) = 27/5
Answer:
i have tried but have no idea
help me too haha
Step-by-step explanation:
