In a geometric progression, the first tern is 81 and the fourth term is 24. find the common ratio

Mathematics

2 answers:

lesantik [10]3 years ago

8 0

Step-by-step explanation:

Oliga [24]3 years ago

4 0

Hello,

Let's say a the first term and r the ratio of the G.P.

$u_1=a=81\\u_2=a*r\\u_3=a*r^2\\u_4=a*r^3\\\\\dfrac{u_4}{u_1} =\dfrac{a*r^3}{a} =r^3=\dfrac{24}{81} =\dfrac{8}{27} \\\\r=\sqrt[3]{\dfrac{8}{27} } \\\\\boxed{r=\dfrac{2}{3}}\\$

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PLEASE HELP

BARSIC [14]

Just do 23 minus 6 and that should be the answer because the y-ccordinate is in the same place

3 0

3 years ago

Please I need this before 12pm

luda_lava [24]

Answer:

The required formula is:

$\ a_{n}=a_{1}+(n-1)d$

Step-by-step explanation:

The total number of squares of the the first term = 4

The total number of squares of the the second term = 7

The total number of squares of the the third term = 10

so,

$a_1=4$

$a_2=7$

$a_3=10$

Finding the common difference d

$d=a_3-a_2=10-7=3$

$d=a_2-a_1=7-4=3$

As the common difference 'd' is same, it means the sequence is in arithmetic.

If the initial term of an arithmetic progression is $a_{1}$ and the common difference of successive members is d, then the nth term of the sequence $(a_n)$ is given by: