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user100 [1]
2 years ago
13

For each of these sequences below: (a) describe the term-to-term rule (b) calculate the tenth term 4.1) 3 6 9 12 15 4.2) 5 11 17

23 29
Mathematics
1 answer:
ratelena [41]2 years ago
6 0

Answer: The term to term rule is an Arithmetic progression for the two question. B) 1Oth term for the first is 30 and for the second series is 59

Step-by-step explanation:

4.1) 3 6 9 12 15

For the sequence above, we can see that the next term is gotten by addition  of 3 with the previous term and so It is an Arithmetic  progression.

Having in mind the nth term of an AP as  Tn = a + (n - 1)d.

where a is the first term =3

And d common difference =3(6-3,9-6,12-9)

10th term=

T10 = 3+ (10 - 1)3.

T10 = 3+ (9)3.

T10 = 3+ 27.

T10 =30

4.2) 5 11 17 23 29

For the sequence above, we can see that the next term is gotten by addition  of 6 with the previous term and so It is an Arithmetic  progression.

Having in mind the nth term of an AP as  Tn = a + (n - 1)d.

where a is the first term =5

And d common difference =6 (11-5, 17-11,23-17)

10th term=

T10 = 5+ (10 - 1)6.

T10 = 5+ (9)6.

T10 = 5+ 54.

T10 =59

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Equation using the quadratic fromula for 0.05x^2 + 1.1x = 250
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Answer:

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Step-by-step explanation:

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0.05x^2 + 1.1x - 250=0

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Plug in the values in the formula

x=\frac{-1.1+-\sqrt{(1.1)^2-4(0.05)(-250)}}{2(0.05)}

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3 years ago
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