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user100 [1]
3 years ago
13

For each of these sequences below: (a) describe the term-to-term rule (b) calculate the tenth term 4.1) 3 6 9 12 15 4.2) 5 11 17

23 29
Mathematics
1 answer:
ratelena [41]3 years ago
6 0

Answer: The term to term rule is an Arithmetic progression for the two question. B) 1Oth term for the first is 30 and for the second series is 59

Step-by-step explanation:

4.1) 3 6 9 12 15

For the sequence above, we can see that the next term is gotten by addition  of 3 with the previous term and so It is an Arithmetic  progression.

Having in mind the nth term of an AP as  Tn = a + (n - 1)d.

where a is the first term =3

And d common difference =3(6-3,9-6,12-9)

10th term=

T10 = 3+ (10 - 1)3.

T10 = 3+ (9)3.

T10 = 3+ 27.

T10 =30

4.2) 5 11 17 23 29

For the sequence above, we can see that the next term is gotten by addition  of 6 with the previous term and so It is an Arithmetic  progression.

Having in mind the nth term of an AP as  Tn = a + (n - 1)d.

where a is the first term =5

And d common difference =6 (11-5, 17-11,23-17)

10th term=

T10 = 5+ (10 - 1)6.

T10 = 5+ (9)6.

T10 = 5+ 54.

T10 =59

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Please help, I will mark!!
Alik [6]

Answer:

d=28.28

Step-by-step explanation:

To calculate the lenght of the diagonal d across the square, we can assume that the square it is compound of two right triangles. So, we can resolve this exercise using The Pythagorean Theorem.

<em>The Pythagorean theorem</em> states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.

If in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relation is fulfilled:

a^{2} +b^{2} =c^{2} a is the height, b is the base, and c is  

the hypotenuse.

To obtain the value of the hypotenuse

c= \sqrt{a^{2} +b^{2} }

To find the value of the lenght of the diagonal d across the square, we have:

d=\sqrt{a^{2} +b^{2} } Where a = b = 20

Substituting the values

d=\sqrt{(20)^{2} +(20)^{2} }\\d=\sqrt{400+400} =\sqrt{800} \\d=28.284

Round the answer to 2 decimal places

d=28.28

6 0
3 years ago
Expand the polynomial:<br> (5a+1/5 b)^2
WINSTONCH [101]
Expand the following:
(5 a + b/5)^2

(5 a + b/5) (5 a + b/5) = (5 a) (5 a) + (5 a) (b/5) + (b/5) (5 a) + (b/5) (b/5):
5×5 a a + (5 a b)/5 + (5 b a)/5 + (b b)/(5×5)

(5 a b)/5 = 5/5×a b = a b:
5×5 a a + a b + (5 b a)/5 + (b b)/(5×5)

(b×5 a)/5 = 5/5×b a = b a:
5×5 a a + a b + b a + (b b)/(5×5)

Combine powers. (b b)/(5×5) = (b^(1 + 1))/(5×5):
5×5 a a + a b + b a + (b^(1 + 1))/(5×5)

1 + 1 = 2:
5×5 a a + a b + b a + (b^2/5)/5

5 a×5 a = 5×5 a^2:
5×5 a^2 + a b + b a + (b^2/5)/5

5×5 = 25:
Answer:  25 a^2 + a b + b a + (b^2/5)/5
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