Explain why -4 is not a real number but -8 is two equations below of what they look like

Mathematics

1 answer:

Margarita [4]3 years ago

7 0

-4 isn't a real number because there is no square root of -4. However, there is a cube root of -8, because -2 * -2 * -2 = -8.

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Brut [27]

$x^{2}$ Answer:

(Explanation)

Step-by-step explanation:

Part A:

The graph of y = $x^{2}$ + 2 will be translated 2 units up from the graph of y = $x^{2}$ .

If you plug in 0 for x, you get a y-value of 2. The 2 is also not included with the $x^{2}$ , which is why it doesn't translate left.

This is what graph A should look like:

[Attached File]

Part B:

The graph of y = $x^{2}$ - 2 will be translated 2 units down from the graph of y = $x^{2}$ .

If you plug in 0 for x, you get a y-value of -2. The 2 is also not included with the $x^{2}$ , which is why it doesn't translate right.

This is what graph B should look like:

[Attached File]

Part C:

The graph of y = 2 $x^{2}$ is a stretched version of the graph y = $x^{2}$ . Numbers that are greater than 1 stretch and open up and numbers less than -1 stretch and open down.

This is what graph C should look like:

[Attached File]

Part D:

The graph of y = $\frac{1}{2}x^{2}$ is a compressed version of the graph y = $x^{2}$ . Numbers that are in-between 0 and 1, and -1 and 0 are compressed.