a new neighborhood activity complex is being built in juctioncity. the perimeter of the rectangular playing field is 362 yards.
1 answer:
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For this case we have the following system of equations:
We can write a system of equivalent equations.
For this, it is enough to multiply one of the two equations by a scalar.
Multiplying the equation 1 by 2, we have:
Therefore, the new system of equations is:
Answer:
A system that is equivalent is:
D)
Answer:
The equation must include -8 as the slope
Step-by-step explanation:
Hi there!
Two key points to keep in mind:
- Linear equations are typically organized in slope-intercept form:
where m is the slope and b is the y-intercept (the value of y when x is 0).
- Parallel lines always have equal slopes
Given the equation y=-8x+6, we can identify that -8 is in the place of m in y=mx+b, making it the slope.
For a line to be parallel to y=-8x+6, it would have to have a slope of -8 as well. This is the only quality a line needs to be parallel to this given line.
I hope this helps!
Answer:
a. V = (20-x)
b . 1185.185
Step-by-step explanation:
Given that:
- The height: 20 - x (in )
- Let x be the length of a side of the base of the box (x>0)
a. Write a polynomial function in factored form modeling the volume V of the box.
As we know that, this is a rectangular box has a square base so the Volume of it is:
V = h *
<=> V = (20-x)
b. What is the maximum possible volume of the box?
To maximum the volume of it, we need to use first derivative of the volume.
<=> dV / Dx = -3 + 40x
Let dV / Dx = 0, we have:
-3 + 40x = 0
<=> x = 40/3
=>the height h = 20/3
So the maximum possible volume of the box is:
V = 20/3 * 40/3 *40/3
= 1185.185