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3 years ago

The point V (-2, 2) is translated 3 units left. what are the coordinates of the resulting point, V?

Mathematics

1 answer:

damaskus [11]3 years ago

3 0

Answer:

V = (-5, 2)

Step-by-step explanation:

Translating it left or right changes the X value, while up and down changes the Y. Which means (-2, 2) translated 3 units left would be (-5, 2)

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Easy question:

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Confused on how to do this, care to help anyone?

ruslelena [56]

Answer:

I would use a proportion for each ingredient:

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4:10=½:x (10×½)÷4= 1,25 cup sugar

Cup brown sugar:

4:10=¼:x (10×¼)÷4= 0.625 cup brown sugar

Peanut butter

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Cup oats

2×¼ = ½

4:10=½:x (10×½)÷4= 1,25 cup oats

Cup milk

4:10=¾:x (10×¾)÷4= 1,875 cup milk

Tsp salt

4:10=1:x (10×1)÷4= 2,5 tsp salt

2 tbsp cocoa

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1 tsp vanilla

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2 eggs

4:10=2:x (10×2)÷4= 5 eggs

3 cups flour

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12 oz nuts

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3 years ago

HELPPPP PLEASE ! GET POINTS AND BRAINLIEST!

erma4kov [3.2K]

Answer:

1. segment RT

2. segment QS

3. segment PS

4. < QTR

5. arc QR

6. arc QSR

7. arc QS

These are all by definition.

Radius: distance from the center of a circle to a point on the circle

Diameter: a chord that goes through the center

Chord: any segment whose endpoints are on the circle

Central Angle: an angle at the center of the circle with endpoints on the circle

Minor Arc: arc that is less than 180 degrees

Major Arc: arc that is greater than 180 degrees

Semicircle: Arc of 180 degrees

4 0

3 years ago

Find all the solutions of the given equations in the interval [0,2pi) tan^3x=tanx and cos 3x=-cos3x

slamgirl [31]

$\tan^3x=\tan x$
$\tan^3x-\tan x=0$
$\tan x(\tan^2x-1)=0$
$\tan x(\tan x-1)(\tan x+1)=0$
$\begin{cases}\tan x=0\\\tan x-1=0\\\tan x+1=0\end{cases}$

$\tan x=\dfrac{\sin x}{\cos x}=0\implies \sin x=0\implies x=0,\pi$

$\tan x-1=0\iff\tan x=1\implies x=\dfrac\pi4,\dfrac{5\pi}4$

$\tan x+1=0\iff\tan x=-1\implies x=\dfrac{3\pi}4,\dfrac{7\pi}4$

- - -

$\cos3x=-\cos3x$
$2\cos3x=0$
$\cos3x=0\implies 3x=\dfrac\pi2,3x=\dfrac{3\pi}2\implies x=\dfrac\pi6,x=\dfrac\pi2$

This doesn't account for all the solutions, however; there are some values of $x$ that push $3x$ outside the interval $[0,2\pi)$ , so let's take a few more:

$3x=\dfrac{5\pi}2\implies x=\dfrac{5\pi}6$
$3x=\dfrac{7\pi}2\implies x=\dfrac{7\pi}6$
$3x=\dfrac{9\pi}2\implies x=\dfrac{9\pi}6$
$3x=\dfrac{11\pi}2\implies x=\dfrac{11\pi}6$

We can stop there, since the next candidate gives

$3x=\dfrac{13\pi}2\implies x=\dfrac{13\pi}6>2\pi$

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3 years ago