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Ronch [10]
3 years ago
10

Anyoneee help im stuck !! 15 points!!

Mathematics
1 answer:
Gnom [1K]3 years ago
6 0

Answer:

Given: \angle 1, \angle 2, \angle 3, \angle 4 formed by two intersecting segments.

In the given figure;

Linear pair states that a pair adjacent angle formed when two lines intersect.

Then by definition of linear pairs,

\angle 1  and  \angle 2 forms a linear pair

Also,  \angle 2  and  \angle 3 forms a linear pair.

Linear pair postulates states that the two angle that forms a linear pair are supplementary(i,e add up to 180 degree).

Then by linear pair postulates;

m\angle 1+ m\angle 2 =180^{\circ}

and

m\angle 2+m \angle 3 =180^{\circ}

Substitution property of equality states that if x =y then, x can be substituted in for y or vice -versa.

then by substitution property of equality:

m\angle 1+m\angle 2=m\angle 2+ m\angle 3

Addition property of equality states that:

if x =y,  then x + z = y+ z

By addition property of equality:

m\angle 1 =m\angle 3     hence proved!

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Answer:

x^2 +y^2 -40x -24y  -81 =0

Step-by-step explanation:

We can write the equation of a circle in the form

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

Assuming that Pamela's cabin is the center

( x-20)^2 + (y- 12)^2 = 25^2

We want to get to general form

x^2 + y^2 + Dx + Ey + F = 0,

Distributing

x^2 -40x +400 + y^2 -24y +144 = 625

x^2 +y^2 -40x -24y +544 -625 =0

x^2 +y^2 -40x -24y  -81 =0

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3 years ago
Two vertical poles of length 10 and 12 ​feet, respectively, stand 17 feet apart. A cable reaches from the top of one pole to the
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Answer:

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433} ft

Step-by-step explanation:

let length of calble = L

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Moving from the top of the 10-foot pole to point x, we have

From the diagram that

x^{2} +10^{2}=L_{1} ^{2}  \\x^{2} + 100 = L_{1} ^{2}

Take the square root of both sides

\sqrt{x^{2}+100}=\sqrt{L_{1} ^{2}}\\  \sqrt{x^{2}+100}= L_{1}

Moving from point x to the top of the 12-foot pole, we have

From the diagram that

(17-x)^{2}+12^{2}=L_{2} ^{2}   \\289-34x+x^{2} +144=L_{2} ^{2}\\x^{2} -34x+433=L_{2} ^{2}

Take the square root of both sides

\sqrt{x^{2}-34x+433}=\sqrt{L_{2} ^{2}}  \\\sqrt{x^{2}-34x+433}=L_{2}

Amount of cable used, L = L1 + L2

L=\sqrt{x^{2}+100}+\sqrt{x^{2}-34x+433}

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Answer:

4.472

Step-by-step explanation:

So we just have to divide

22.36 / 5 = 4.472

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Answer:

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