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Ad libitum [116K]
3 years ago
8

Find the difference of functions s and r shown

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
7 0

Answer & Step-by-step explanation:

In this problem, we are given two functions.

<em>s(x) = 2x + 1</em>

<em>r(x) = -x² + 3x</em>

We are asked to find the difference between s(x) and r(x).

<em>(2x + 1) - (-x² + 3x)</em>

Distribute the negative to the second parentheses.

<em>2x + 1 + x² - 3x</em>

Combine like terms and put the equation in standard form. This means the exponents should be in descending order.

<em>x² - x + 1</em>

So, (s - r)(x) equals x² - x + 1

<em />

Fiesta28 [93]3 years ago
3 0

Answer:

(2x-1) - (-x^2 +3x)

THEN

x^2  - x + 1

Step-by-step explanation:

Since youre subtracting r from s...

s(x) = 2x + 1

r(x) = -x^2 + 3x

you subtract the two to get an equation for the first step.

(s-r)(x) = (2x+1) - (-x^2 +3x)

for the next step, you're simplifying...

distribute the minus: (2x+1) + x^2 - 3x

combine like terms: x^2 + 1 - 1x

which gives you the answer of...

x^2  - x + 1

Hope this helps!!

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